我想用Numberfields和一个按钮创建一个Java程序。 单击按钮时,它等待和放在Numberfield中的时间。整数工作正常,但该功能不起作用。
以下是代码:
public void jButton1_ActionPerformed(ActionEvent evt) {
sekunden = Integer.parseInt(jNumberField3.getText());
minuten = Integer.parseInt(jNumberField2.getText());
stunden = Integer.parseInt(jNumberField1.getText());
zeit = sekunden + minuten*60 + stunden*60*60;//berechnet die zeit in sekunden
TimeUnit.SECONDS.sleep(zeit);//here is the error
System.out.println("zeit");
} // end of jButton1_ActionPerformed
错误消息如下所示:
ES.java:78:27: error: unreported exception InterruptedException; must be caught or declared to be thrown TimeUnit.SECONDS.sleep(zeit);
答案 0 :(得分:1)
方法调用TimeUnit.SECONDS.sleep(zeit)
抛出必须被捕获的InterruptedException
:
public void jButton1_ActionPerformed(ActionEvent evt) {
try {
sekunden = Integer.parseInt(jNumberField3.getText());
minuten = Integer.parseInt(jNumberField2.getText());
stunden = Integer.parseInt(jNumberField1.getText());
zeit = sekunden + minuten*60 + stunden*60*60;//berechnet die zeit in sekunden
TimeUnit.SECONDS.sleep(zeit);//here is the error
System.out.println("zeit");
}catch (InterruptedException e){
//handle the exception
}
}
答案 1 :(得分:1)
您需要处理拨打InterruptedException
时可能发生的潜在sleep()
。这就是您的代码出现编译错误的原因。
请查看有关JavaDocs的Catching and Handling Exceptions以了解有关异常处理的更多详细信息。
在您的情况下,您可以通过处理异常(例如:
)轻松解决此问题public void jButton1_ActionPerformed(ActionEvent evt) {
sekunden = Integer.parseInt(jNumberField3.getText());
minuten = Integer.parseInt(jNumberField2.getText());
stunden = Integer.parseInt(jNumberField1.getText());
zeit = sekunden + minuten*60 + stunden*60*60;//berechnet die zeit in sekunden
try {
// tries to call sleep
TimeUnit.SECONDS.sleep(zeit);//here is the error
} catch (InterruptedException e) {
// handles any possible exception during the call to "sleep()"
e.printStackTrace(); // prints the exception stack trace to the console
}
System.out.println("zeit");
} // end of jButton1_ActionPerformed
异常处理中的一些好参考是: