Question

我有两张桌子：

ConnectionID（CID）
AuditLog（AL）

如果CID在过去15分钟内没有where CID.UserID = AL.UserID，我想对CID.UserID表AL.RecordDate中的所有行执行删除语句。

我没有成功尝试过......

declare @15min datetime 
set @15min = dateadd(minute,-15,getdate())

Delete ConnectionID CID
inner join AuditLog as AL on CID.UserID = AL.UserID
Where AL.RecordDate < @15Min AND AL.UserID in CID.UserID

我不是编写SQL语句的专家，因此非常感谢任何建议。谢谢！

Answer 1

那么，您希望不删除在过去15分钟内有活动的任何连接？（与您在问题中尝试更接近＆＃34;删除任何连接的任何活动超过15分钟前＆＃34;）。

应该是这样的：

WITH RecentActivity as (
    SELECT DISTINCT UserID FROM AuditLog
    WHERE RecordDate >= DATEADD(minute,-15,GETDATE())
)
DELETE FROM CID
FROM ConnectionID CID
       LEFT JOIN
     RecentActivity RA
       on
          CID.UserID=  RA.UserID
WHERE
    RA.UserID is NULL

Answer 2

您可以像这样使用NOT EXISTS。

declare @min15 datetime 
set @min15 = dateadd(minute,-15,getdate())
Delete CID FROM ConnectionID CID
WHERE NOT EXISTS
(
SELECT TOP 1 1 FROM AuditLog as AL
WHERE AL.UserID = CID.UserID
AND AL.RecordDate > @Min15
)

删除带参数的T SQL语句

2 个答案: