Question

我希望能够根据数组的内容创建文件。这是我尝试过的：

class make_files (
    $servers = ['server-1','server-2','server-3'],
) {
    file { $servers :
        path    => '/tmp',
        content => $servers,
    }
}

...但是当我这样执行时......

# puppet apply --modulepath=/root/modules -e 'include make_files'

...我得到了这个输出：

Notice: Compiled catalog for host-001 in environment production in 0.13 seconds
Error: Cannot alias File[server-2] to ["/tmp"] at /root/modules/make_files/manifests/init.pp:9; resource ["File", "/tmp"] already declared at /root/modules/make_files/manifests/init.pp:9

我希望有三个档案......

# ls /tmp/server-?
/tmp/server-1  /tmp/server-2  /tmp/server-3
# cat /tmp/server-?
server-1
server-2
server-3

如果有人能告诉我如何命名文件，那将真的很酷：server-1.cfg，server-2.cfg和server-3.cfg。感谢任何帮助！

Answer 1

首先，您已在File['/tmp']文件中定义了资源init.pp。这是导致问题的主要原因：

错误：无法在/root/modules/make_files/manifests/init.pp:9将文件[server-2]别名为[“/ tmp”];资源[“File”，“/ tmp”]已在/root/modules/make_files/manifests/init.pp:9中声明

请检查path属性的含义。也许这会澄清问题。创建

$files_to_create = ['/path/server-1','/path/server-2','/path/server-3']

然后使用它：

    file { $files_to_create :
        content => $servers,
    }

还请确保文件系统中已存在/path目录。到目前为止，puppet无法创建中间目录。

如何基于puppet数组内容生成文件？

1 个答案: