如何将多个结果合并到一列?
例如,我的查询显示以下结果:
internaldocid | document id | versionid | title | tagname
1146 | DOC-1146 | 2 | Press Release | tag1
1146 | DOC-1146 | 2 | Press Release | tag2
1146 | DOC-1146 | 2 | Press Release | tag3
我希望它能显示这个结果:
internaldocid | document id | versionid | title | tagname
1146 | DOC-1146 | 2 | Press Release | tag1, tag2, tag3
这是我的SQL:
SELECT
cmsdocument.internaldocid,
cmsdocument.documentid,
cmsdocument.versionid,
cmsdocversion.title,
cmstag.tagname
FROM
public.cmsobjecttag,
public.cmstag,
public.cmsdocument,
public.cmsdocversion,
public.cmsuser
WHERE
cmsobjecttag.tagid = cmstag.tagid AND
cmsobjecttag.objectid = cmsdocument.internaldocid AND
cmsdocument.internaldocid = cmsdocversion.internaldocid AND
cmsdocument.userid = cmsuser.userid AND
cmsdocversion.state = 'published' AND
cmsobjecttag.objecttype = '102';
非常感谢任何帮助。
答案 0 :(得分:2)
自PostgreSQL版本9以来,只需使用string_agg:
即可完成SELECT
cmsdocument.internaldocid,
cmsdocument.documentid,
cmsdocument.versionid,
cmsdocversion.title,
string_agg(cmstag.tagname, ',')
FROM
public.cmsobjecttag,
public.cmstag,
public.cmsdocument,
public.cmsdocversion,
public.cmsuser
WHERE
cmsobjecttag.tagid = cmstag.tagid AND
cmsobjecttag.objectid = cmsdocument.internaldocid AND
cmsdocument.internaldocid = cmsdocversion.internaldocid AND
cmsdocument.userid = cmsuser.userid AND
cmsdocversion.state = 'published' AND
cmsobjecttag.objecttype = '102'
GROUP BY
cmsdocument.internaldocid,
cmsdocument.documentid,
cmsdocument.versionid,
cmsdocversion.title