Question

我正在编写一个查询，它将在上周查看并选择一个值，并给我计算它被使用...非常简单的概念，除了当我运行查询时，我得到一个结果，系统不是'上周使用了！

SELECT re.topic, COUNT(*) AS TimesUsed 
FROM ost_ticket AS us
  JOIN ost_help_topic AS re ON re.topic_id = us.topic_id
WHERE re.created  >= CURDATE() - INTERVAL (WEEKDAY(CURDATE())+7) DAY
  AND re.created  <  CURDATE() - INTERVAL (WEEKDAY(CURDATE())) DAY
GROUP BY us.topic_id  ORDER BY TimesUsed DESC LIMIT 1

我可以确认上周没有门票，因为当我运行查询以查看上周是否创建了任何答案为空时。

SELECT number
FROM ost_ticket
WHERE created  >= CURDATE() - INTERVAL (WEEKDAY(CURDATE())+7) DAY
  AND created  <  CURDATE() - INTERVAL (WEEKDAY(CURDATE())) DAY;

所以我的问题基本上是我在日期选择上做错了以获得最后几周的日期？

Answer 1

您正在混合dos2unix和日期值。如果您想检查系统是否在上周使用，只需从intervals中减去7天的时间间隔：

curdate()

Answer 2

我能够从select语句中选择以获取自上一个星期一以来的日期所需的列。

SELECT 
    t1.topic
FROM
    (SELECT 
        re.topic AS topic, COUNT(*) AS TimesUsed
    FROM
        ost_ticket AS us
    JOIN ost_help_topic AS re ON re.topic_id = us.topic_id
    WHERE
        re.created BETWEEN DATE(DATE_SUB(DATE_SUB(NOW(), INTERVAL ((7 + WEEKDAY(DATE_SUB(NOW(), INTERVAL 1 WEEK)) - 4) % 7) DAY), INTERVAL 4 DAY)) AND DATE_FORMAT(DATE_SUB(NOW(), INTERVAL ((7 + WEEKDAY(DATE_SUB(NOW(), INTERVAL 1 WEEK)) - 4) % 7) DAY), '%Y-%m-%d')
    GROUP BY us.topic_id
    ORDER BY TimesUsed DESC
    LIMIT 1) t1;

MySQL返回值应该是空的

2 个答案: