我想操纵Stdin
然后Std*
。但是我收到了以下错误,
$ gcc testFd.c
testFd.c:9: error: initializer element is not constant
testFd.c:9: warning: data definition has no type or storage class
testFd.c:10: error: redefinition of `fd'
testFd.c:9: error: `fd' previously defined here
testFd.c:10: error: `mode' undeclared here (not in a function)
testFd.c:10: error: initializer element is not constant
testFd.c:10: warning: data definition has no type or storage class
testFd.c:12: error: syntax error before string constant
该计划如下所示。
#include <stdio.h>
#include <sys/ioctl.h>
int STDIN_FILENO = 1;
// I want to access typed
// Shell commands, dunno about the value:
unsigned long F_DUPFD;
fd = fcntl(STDIN_FILENO, F_DUPFD, 0);
fd = open("/dev/fd/0", mode);
printf("STDIN = %s", fd);
更新了错误:只是尝试获取一个关于文件描述符的示例程序在C中工作,错误的报告
#include <stdio.h>
#include <sys/ioctl.h>
int main (void) {
int STDIN_FILENO;
// I want to access typed
// Shell commands, dunno about the value:
unsigned long F_DUPFD;
int fd;
const char mode = 'r';
fd = fcntl(STDIN_FILENO, F_DUPFD, 0);
/* also, did you mean `fopen'? */
fd = fopen("/dev/fd/0", mode);
printf("STDIN = %s", fd);
return 0;
}
程序执行如下所示。
$ gcc testFd.c
testFd.c: In function `main':
testFd.c:14: warning: passing arg 2 of `fopen' makes pointer from integer without a cast
testFd.c:14: warning: assignment makes integer from pointer without a cast
答案 0 :(得分:3)
尝试使用main
方法:
#include <stdio.h>
#include <sys/ioctl.h>
int main (void) {
int STDIN_FILENO = 1;
// I want to access typed
// Shell commands, dunno about the value:
unsigned long F_DUPFD;
/* also, declare the type of your variable "fd" */
int fd;
fd = fcntl(STDIN_FILENO, F_DUPFD, 0);
/* also, did you mean `fopen'? */
fd = open("/dev/fd/0", mode);
printf("STDIN = %s", fd);
return 0;
}
答案 1 :(得分:2)
你忘记了你的main()函数!!
答案 2 :(得分:2)
您对main()
的定义在哪里?
答案 3 :(得分:2)
除了您没有main()
功能之外,您的整个方法都是错误的。 STDIN_FILENO
是一个常数;分配它没有任何意义。
尝试详细解释您实际想要做什么的内容,我们将能够建议如何去做。