Question

我试图定义一个自定义的ORDERY BY城市。

这样的事情：

New York (255)
Paris (26)
Vien(15)

然后ORDER BY city ASC。

我已经尝试过此查询，但它无法正常工作：

SELECT count(id_item) as q, city FROM item GROUP BY city ORDER BY FIELD(city,'New York','Paris','Vien'), city ASC

Answer 1

你可以这样做：

SELECT 
    count(id_item) as q, 
    city 
FROM 
    item 
GROUP BY 
    city 
ORDER BY
    ( 
        CASE 
            WHEN city='New York' THEN 1
            WHEN city='Paris' THEN 2
            WHEN city='Vien' THEN 3
            ELSE 4
        END
    ) ASC,
    city ASC

Answer 2

ORDER BY关键字默认按升序对记录进行排序。要按降序对记录进行排序，可以使用DESC关键字。试试这个 -

SELECT count(id_item) as q, city FROM item GROUP BY city ORDER BY city;

对于下降，你可以做这样的事情 -

SELECT count(id_item) as q, city FROM item GROUP BY city ORDER BY city DESC;

要使用自己的首选顺序获取行，SELECT查询将如下所示：

SELECT 
    count(id_item) as q, 
    city 
FROM 
    item 
GROUP BY 
    city 
ORDER BY
    ( 
        CASE 
            WHEN city='New York' THEN 1
            WHEN city='Paris' THEN 2
            WHEN city='Vien' THEN 3
            ELSE 4
        END
    ) ASC,
    city ASC

Answer 3

你可以order by city='New York' desc, city='Paris' desc, city='Vien' desc, city

甚至order by city in ('New York', 'Paris', 'Vien') desc, city因为这3个已经按字母顺序排列

按城市定义自定义订单

3 个答案: