Question

我有一个包含HTML代码的页面：

<ul class ='trainList'>
<li>
    <div class="smallFont farelist no-discount ">
        <div class="train-no">ABC 701</div>
        <div class="train-time">06:10<br>07:15</div>
        <div class="train-info">
            <div class="box">
                <div class="total-price">MYR 50.00</div>
                <div class="farediscount">
                    <div class="actual-fare-price">Array</div>
                    <div class="train-discount"></div>
                </div>
            </div>
</li>
<li>
    <div class="smallFont farelist no-discount ">
        <div class="train-no">ABC 701</div>
        <div class="train-time">06:10<br>07:15</div>
        <div class="train-info">
            <div class="box">
                <div class="total-price">MYR 50.00</div>
                <div class="farediscount">
                    <div class="actual-fare-price">Array</div>
                    <div class="train-discount"></div>
                </div>
            </div>
</li>

我想从上面的代码中搜索和提取火车号码，训练时间和火车价格。

我的代码没有抓取我想要的信息，但给了我空白。我检查了之前发过的很多问题，但我找不到类似的东西。

我的代码：

 $train_doc = new DOMDocument();

libxml_use_internal_errors(TRUE); 

if(!empty($html)){ 

  $train_doc->loadHTML($html);

  libxml_clear_errors(); 

  $train_xpath = new DOMXPath($train_doc);


  $train_list = array();

$train = $train_xpath->query('//div[@class="smallFont farelist no-discount"]');
var_dump($train);
if($train->length > 0){   


  foreach($train as $pat){

      $name = $train_xpath->query('div[@class="train-no"]', $pat)->item(0)->nodeValue;

      $train_types = array(); 
      $types = $train_xpath->query('div[@class="train-time"]/a', $pat);


      foreach($types as $type){
          $train_types[] = $type->nodeValue; 


      $train_list[] = array('name' => $name, 'types' => $train_types);

  }
}
}

echo "<pre>";
print_r($train_list);
echo "</pre>";

Answer 1

首先需要指向元素，首先获取每个li然后指向所需的元素：

numberA

Sample Output

Answer 2

{{1}}

希望这有帮助

如何使用PHP从ul li标签中抓取每个数据值？

2 个答案: