我正在使用javascript Date对象尝试将毫秒转换为多少小时,分钟和秒。
我有以毫秒为单位的currentTime
var currentTime = new Date().getTime()
我的futureTime以毫秒为单位
var futureTime = '1432342800000'
我想以毫秒为单位获得差异
var timeDiff = futureTime - currentTime
timeDiff
timeDiff = '2568370873'
我想知道它是多少小时,分钟,秒。
有人可以帮忙吗?
答案 0 :(得分:10)
var secDiff = timeDiff / 1000; //in s
var minDiff = timeDiff / 60 / 1000; //in minutes
var hDiff = timeDiff / 3600 / 1000; //in hours
已更新
function msToHMS( ms ) {
// 1- Convert to seconds:
var seconds = ms / 1000;
// 2- Extract hours:
var hours = parseInt( seconds / 3600 ); // 3,600 seconds in 1 hour
seconds = seconds % 3600; // seconds remaining after extracting hours
// 3- Extract minutes:
var minutes = parseInt( seconds / 60 ); // 60 seconds in 1 minute
// 4- Keep only seconds not extracted to minutes:
seconds = seconds % 60;
alert( hours+":"+minutes+":"+seconds);
}
var timespan = 2568370873;
msToHMS( timespan );
<强> Demo 强>
答案 1 :(得分:2)
将ms转换为hh:mm:ss
function millisecondsToHuman(ms) {
const seconds = Math.floor((ms / 1000) % 60);
const minutes = Math.floor((ms / 1000 / 60) % 60);
const hours = Math.floor((ms / 1000 / 3600 ) % 24)
const humanized = [
pad(hours.toString(), 2),
pad(minutes.toString(), 2),
pad(seconds.toString(), 2),
].join(':');
return humanized;
}
=
答案 2 :(得分:0)
时间的差异以毫秒为单位: Get time difference between two dates in seconds
要获得差异,你必须使用math.floor() http://www.w3schools.com/jsref/jsref_floor.asp
var secDiff = Math.floor(timeDiff / 1000); //in s
var minDiff = Math.floor(timeDiff / 60 / 1000); //in minutes
var hDiff = Math.floor(timeDiff / 3600 / 1000); //in hours
答案 3 :(得分:0)
var timediff = futureTime - currentTime
long seconds = (long) (timediff / 1000) % 60 ;
long minutes = (long) ((timediff / (1000*60)) % 60);
long hours = (long) ((timediff / (1000*60*60)) % 24);
if(hours>0)
time = hours+" hrs : "+minutes+" mins";
else if(minutes>0)
time = minutes+" mins";
else if(seconds>0)
time = seconds+" secs";
答案 4 :(得分:0)
function msToHMS( duration ) {
var milliseconds = parseInt((duration % 1000) / 100),
seconds = parseInt((duration / 1000) % 60),
minutes = parseInt((duration / (1000 * 60)) % 60),
hours = parseInt((duration / (1000 * 60 * 60)) % 24);
hours = (hours < 10) ? "0" + hours : hours;
minutes = (minutes < 10) ? "0" + minutes : minutes;
seconds = (seconds < 10) ? "0" + seconds : seconds;
return hours + ":" + minutes + ":" + seconds ;
}
答案 5 :(得分:0)
如果您确信该期间将始终少于一天,则可以使用这种单线:
new Date(timeDiff).toISOString().slice(11,19) // HH:MM:SS
N.B。如果timeDiff
大于一天,这将是错误的。
答案 6 :(得分:0)
这是一个简单的函数
function simplifiedMilliseconds(milliseconds) {
const totalSeconds = parseInt(Math.floor(milliseconds / 1000));
const totalMinutes = parseInt(Math.floor(totalSeconds / 60));
const totalHours = parseInt(Math.floor(totalMinutes / 60));
const days = parseInt(Math.floor(totalHours / 24));
const seconds = parseInt(totalSeconds % 60);
const minutes = parseInt(totalMinutes % 60);
const hours = parseInt(totalHours % 24);
let time = '1s';
if (days > 0) {
time = `${days}d:${hours}h:${minutes}m:${seconds}s`;
} else if (hours > 0) {
time = `${hours}h:${minutes}m:${seconds}s`;
} else if (minutes > 0) {
time = `${minutes}m:${seconds}s`;
} else if (seconds > 0) {
time = `${seconds}s`;
}
return time;
}
答案 7 :(得分:0)
将毫秒转换为 DD(days):HH:MM:SS
function formatTime(timeMS) {
const [MS_IN_SEC, SEC_IN_DAY, SEC_IN_HOUR, SEC_IN_MIN] = [1000, 86400, 3600, 60];
let seconds = Math.round(Math.abs(timeMS) / MS_IN_SEC);
const days = Math.floor(seconds / SEC_IN_DAY);
seconds = Math.floor(seconds % SEC_IN_DAY);
const hours = Math.floor(seconds / SEC_IN_HOUR);
seconds = Math.floor(seconds % SEC_IN_HOUR);
const minutes = Math.floor(seconds / SEC_IN_MIN);
seconds = Math.floor(seconds % SEC_IN_MIN);
const [dd, hh, mm, ss] = [days, hours, minutes, seconds]
.map(item => item < 10 ? '0' + item : item.toString());
return dd + ':' + hh + ':' + mm + ':' + ss;
}