所以我对Symfony很陌生,我试图让控制器根据控制器动作构建略有不同的形式。现在,我有这个
//in Controller
public function addLocationEntryAction(Request $request)
{
$entry = new Entry();
$form = $this->get('form.factory')->create(new EntryType('addLocation'), $entry);
return $this->render('OOTNBlogBundle:Blog:addEntry.html.twig', array(
'form' => $form->createView()
));
}
public function addArticleEntryAction(Request $request)
{
$entry = new Entry();
$form = $this->get('form.factory')->create(new EntryType('addArticle'), $entry);
return $this->render('OOTNBlogBundle:Blog:addEntry.html.twig', array(
'form' => $form->createView()
));
}
并且
//in EntryType
public function buildForm(FormBuilderInterface $builder, array $options)
{
$builder
->add('title', 'text')
->add('continent', 'text', array('required' => false))
->add('country', 'text', array('required' => false))
->add('category', 'text', array('required' => false))
->add('author', 'hidden')
->add('type', 'hidden')
->add('text', 'textarea')
->add('post', 'submit')
;
}
我想从buildForm
中的控制器传递一个选项,以便我可以这样做:
public function buildForm(FormBuilderInterface $builder, array $options, $option)
{
$builder
->add('title', 'text')
;
if($option == 'addLocation')
{
$builder
->add('continent', 'text', array('required' => false))
->add('country', 'text', array('required' => false))
;
}
elseif($option == 'addArticle')
{
$builder
->add('category', 'text', array('required' => false))
;
}
$builder
->add('author', 'hidden')
->add('type', 'hidden')
->add('text', 'textarea')
->add('post', 'submit')
;
}
我该怎么做?我已经在这里检查了Symfony doc和类似的问题,但似乎没有什么比我的情况更合适。我不知道。
答案 0 :(得分:16)
无需创建其他参数,只需使用options
传递自定义数据即可。在以下示例中,我将age
属性设置为必需,您可以将其设置为可选或指定默认值。详细了解OptionsResolver
here
class ExampleType extends AbstractType
{
public function buildForm(FormBuilderInterface $builder, array $options)
{
var_dump($options['age']);
}
public function setDefaultOptions(OptionsResolverInterface $resolver)
{
$resolver->setRequired(array(
'age'
));
}
}
创建:
$form = $this->get('form.factory')->create(new ExampleType(), $entry, array(
'age' => 13
));