Question

我目前正在尝试发布一个php web服务，它将查询一个mysql数据库并且[应该]返回一个字符串值。我已经研究过AFNetworking但是不了解如何使用从查询返回的值。例如：

 AFHTTPRequestOperationManager *manager = [AFHTTPRequestOperationManager manager];
[manager POST:@"http://samwize.com/api/poo/"
parameters:@{@"color": @"green"}
  success:^(AFHTTPRequestOperation *operation, id responseObject) {
NSLog(@"JSON: %@", responseObject);
} failure:^(AFHTTPRequestOperation *operation, NSError *error) {
NSLog(@"Error: %@", error);
}];

我猜我操纵responseObject来获取我想要的字符串？任何帮助将不胜感激

Answer 1

AFHTTPRequestOperationManager *manager = [AFHTTPRequestOperationManager manager];
        [manager POST:@"http://samwize.com/api/poo/"
           parameters:@{@"color": @"green"}
              success:^(AFHTTPRequestOperation *operation, id responseObject) {
                  NSError *error = nil;
                  NSDictionary *JSON = [NSJSONSerialization JSONObjectWithData:responseObject options:NSJSONReadingAllowFragments error:&error];
                  if (error) {
                      NSLog(@"Error serializing %@", error);
                  }
                  NSLog(@"JSON: %@", JSON);
              } failure:^(AFHTTPRequestOperation *operation, NSError *error) {
                  NSLog(@"Error: %@", error);
              }];

这会将您的JSON回复转换为NSDictionary

iOS AFNetworking发布麻烦

1 个答案: