Question

我在片段中使用了这个http://www.knockmeout.net/2013/01/simple-editor-pattern-knockout-js.html，但是当我运行应用程序时，SwipeMenuListView没有显示其内容，在堆栈中我发现有些人在onCreateView方法中使用listview，我尝试了但是它不起作用

public class AutorizadasFragment extends Fragment {

    private SwipeMenuListView listView;
    private CustomArrayAdapter adapter;
    private List<String> data;

    public AutorizadasFragment() {
    }

    @Override
    public View onCreateView(LayoutInflater inflater, ViewGroup container,
                             Bundle savedInstanceState) {

        View rootView = inflater.inflate(R.layout.fragment_autorizadas, container, false);


        return rootView;
    }


    @Override
    public void onActivityCreated(Bundle savedInstanceState) {
        // TODO Auto-generated method stub
        super.onActivityCreated(savedInstanceState);

        data = new ArrayList<String>();

        data.add("Teste 1");
        data.add("Teste 2");
        data.add("Teste 3");
        data.add("Teste 4");
        data.add("Teste 5");

        listView = (SwipeMenuListView) getActivity().findViewById(R.id.list);

        adapter = new CustomArrayAdapter(getActivity(), data);
        listView.setAdapter(adapter);
        SwipeMenuCreator creator = new SwipeMenuCreator() {

            @Override
            public void create(SwipeMenu menu) {
                // create "open" item
                SwipeMenuItem openItem = new SwipeMenuItem(
                        getActivity());
                // set item background
                openItem.setBackground(new ColorDrawable(Color.rgb(0xC9, 0xC9,
                        0xCE)));
                // set item width
                openItem.setWidth(90);
                // set item title
                openItem.setTitle("Open");
                // set item title fontsize
                openItem.setTitleSize(18);
                // set item title font color
                openItem.setTitleColor(Color.BLACK);
                // add to menu
                menu.addMenuItem(openItem);

                // create "delete" item
                SwipeMenuItem deleteItem = new SwipeMenuItem(
                        getActivity());
                // set item background
                deleteItem.setBackground(new ColorDrawable(Color.rgb(0xF9,
                        0x3F, 0x25)));
                // set item width
                deleteItem.setWidth(90);
                // set a icon
                deleteItem.setIcon(R.drawable.ic_exit);
                // add to menu
                menu.addMenuItem(deleteItem);
            }
        };

        listView.setMenuCreator(creator);
    }


    @Override
    public void onCreateOptionsMenu(Menu menu, MenuInflater inflater) {
        // TODO Auto-generated method stub
        super.onCreateOptionsMenu(menu, inflater);
        inflater.inflate(R.menu.menu_main, menu);


    }
}

XML：

 <LinearLayout
        style="@style/FormRegister"
        android:orientation="vertical"
        android:weightSum="1"
        android:layout_width="fill_parent"
        android:layout_height="fill_parent">

        <com.baoyz.swipemenulistview.SwipeMenuListView
            android:id="@+id/list"
            android:layout_width="fill_parent"
            android:layout_height="match_parent"
            android:scrollbars="vertical"/>
</LinearLayout>

Answer 1

您可以通过添加私有属性来保存对根视图的引用 e.g。

private View rootView = null;

并更改onCreateView中的以下行：

View rootView = inflater.inflate(R.layout.fragment_autorizadas, container, false);

到

rootView = inflater.inflate(R.layout.fragment_autorizadas, container, false);

然后你不需要使用＆＃34; getActivity（）。findViewById（R.id.list）;＆＃34; （它将成为＆＃34; rootView.findViewById（R.id.list）;＆＃34;）

我建议这样做是因为我不确定在调用onActivityCreated（）时，onCreateView中创建的视图是否实际上已添加到您的活动根视图中。

片段中的ListView未显示

1 个答案: