Question

当我试图获得一个Entitymanager时，我总是变成一个NamingException ..这就是它崩溃的地方:(在查找函数中）

try {
      ctx = new InitialContext();
      entityManager = (EntityManager)ctx.lookup("java:/comp/env/myExample");
    } catch (NamingException namingException) {
      throw new NamingException();
    }

我的persistence.xml：

<?xml version="1.0" encoding="UTF-8"?>
<persistence version="2.0"
    xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd">

    <persistence-unit name="myExample">
        <provider>org.apache.openjpa.persistence.PersistenceProviderImpl</provider>
        <jta-data-source>DSLDB</jta-data-source>
        <mapping-file>META-INF/interface_orm.xml</mapping-file>

        <properties>
            <property name="openjpa.jdbc.UpdateManager" value="operation-order" />
            <property name="openjpa.FlushBeforeQueries" value="false" />
            <property name="openjpa.OrphanedKeyAction" value="none" />
            <property name="openjpa.ConnectionRetainMode" value="transaction" />
            <property name="openjpa.jdbc.DBDictionary" value="useNativeSequenceCache=true" />
        </properties>
    </persistence-unit>
</persistence>

persistence.xml位于META-INF文件夹中的lib组件下。

我还在deploy.xml中定义了数据源：

<datasource database="oracle">
            <jndi_id value="DSLDB"/>

            <user value="user"/>
<!--            <user value="user1"/> -->

            <password value="password"/>

            <jdbc_url value="jdbc:oracle:thin:@//skjdfhsdhf2009-skip.moage.org:1522/WKFISAS.nittaschoa.net"/> <!-- JAP7 IT -->

            <transaction_protocol value="EmulateTwoPhaseCommit" />
            <!--
            <driver_class value="oracle.jdbc.OracleDriver" />
            <support_xa_transaction value="true" />
            <transaction_protocol value="None" />
            <test_table value=" SQL SELECT 1 FROM DUAL" />
            -->
        </datasource>

查找EntityManager后出现NamingException

0 个答案: