Question

我收到以下错误，我不知道原因：

1064 - 您的SQL语法出错;检查与MySQL服务器版本对应的手册，以获得正确的语法靠近';

DELIMITER $$

CREATE PROCEDURE staffnewid_all()
BEGIN
DECLARE x int;
DECLARE y int;
DECLARE z int;

DECLARE charid varchar;
DECLARE a int;
DECLARE b int;

DROP TEMPORARY TABLE IF EXISTS cms_psm.temp_nostaf;

CREATE TEMPORARY TABLE IF NOT EXISTS cms_psm.temp_nostaf (tempid INTEGER NOT   NULL AUTO_INCREMENT PRIMARY KEY, char_id varchar(1));

INSERT INTO cms_psm.temp_nostaf (char_id) SELECT DISTINCT(LEFT(nostaf, 1)) FROM staf_new_no;

SET a = (SELECT min(tempid) FROM cms_psm.temp_nostaf ORDER BY tempid);
SET b = (SELECT COUNT(tempid) FROM cms_psm.temp_nostaf);


WHILE a<=b DO

SET charid = (SELECT char_id FROM cms_psm.temp_nostaf WHERE tempid=a);

SET x = (SELECT count(*) FROM staf_peribadi WHERE nostaf LIKE CONCAT('%', charid, '%') ORDER BY nostaf ASC);
SET y = (SELECT min(id) FROM staf_new_no WHERE nostaf LIKE CONCAT('%', charid, '%') ORDER BY nostaf ASC);
SET z = 1;



WHILE z<=x DO
  UPDATE staf_new_no SET nostaf_new = CONCAT(charid, LPAD(z, 6, '0')) WHERE id=y;
  SET z = z + 1 ;
  SET y = y + 1 ;
END WHILE;

SET a = a + 1 ;

END WHILE;

END

Answer 1

使用语句

结束您的代码

END;$$ 
Delimiter ;

它有效

Answer 2

实际上我忘了这个

DECLARE charid varchar;

应该是

DECLARE charid varchar(1);

感谢您的帮助

Answer 3

BEGIN
DECLARE x int;
DECLARE y int;
DECLARE z int;
DECLARE a int;
DECLARE b int;
DECLARE charid varchar(1);

DROP TEMPORARY TABLE IF EXISTS temp_nostaf;

CREATE TEMPORARY TABLE IF NOT EXISTS temp_nostaf (tempid INTEGER NOT NULL AUTO_INCREMENT PRIMARY KEY, char_id varchar(1));

INSERT INTO temp_nostaf (char_id) SELECT DISTINCT(LEFT(nostaf, 1)) FROM staf_new_no;

SET a = (SELECT min(tempid) FROM cms_psm.temp_nostaf ORDER BY tempid);
SET b = (SELECT COUNT(tempid) FROM cms_psm.temp_nostaf);


WHILE a<=b DO

SET charid = (SELECT char_id FROM cms_psm.temp_nostaf WHERE tempid=a);

SET x = (SELECT count(*) FROM staf_peribadi WHERE nostaf LIKE CONCAT('%', charid, '%') ORDER BY nostaf ASC);
SET y = (SELECT min(id) FROM staf_new_no WHERE nostaf LIKE CONCAT('%', charid, '%') ORDER BY nostaf ASC);
SET z = 1;



WHILE z<=x DO
  UPDATE staf_new_no SET nostaf_new = CONCAT(charid, LPAD(z, 6, '0')) WHERE id=y;
  SET z = z + 1 ;
  SET y = y + 1 ;
END WHILE;

SET a = a + 1 ;

END WHILE;

END

MySQL过程中分号的语法错误

3 个答案: