我正在创建一个包含多个persp图的面板,每个图显示通过调整复杂回归模型中的预测变量生成的一系列数据。我希望我的3D表面由我的z变量进行颜色编码,我能够轻松地做到这一点。如何使用此色标并使其覆盖我面板中所有绘图所代表的所有z变量值的范围,以便可以比较多个persp图之间的色标?
#colorized z scale, only a smidge modified from http://www.inside-r.org/r-doc/graphics/persp
par(bg = "white")
par(mfrow=c(1,2))
x <- seq(-1.95, 1.95, length = 30)
y <- seq(-1.95, 1.95, length = 35)
z1 <- outer(x, y, function(a, b) a*b^2)
nrz <- nrow(z1)
ncz <- ncol(z1)
# Create a function interpolating colors in the range of specified colors
jet.colors <- colorRampPalette( c("blue", "green") )
# Generate the desired number of colors from this palette
nbcol <- 100
color <- jet.colors(nbcol)
# Compute the z-value at the facet centres
zfacet <- z1[-1, -1] + z1[-1, -ncz] + z1[-nrz, -1] + z1[-nrz, -ncz]
# Recode facet z-values into color indices
facetcol <- cut(zfacet, nbcol)
persp(x, y, z1, zlim=c(-8, 10.5), col = color[facetcol], phi = 30, theta = -30)
#zlim added to encompass combined ranges of z1 and z2
#exact same code, with different values of z
x <- seq(-1.95, 1.95, length = 30)
y <- seq(-1.95, 1.95, length = 35)
z2 <- outer(x, y, function(a, b) a*b^2+3)
nrz <- nrow(z2)
ncz <- ncol(z2)
# Create a function interpolating colors in the range of specified colors
jet.colors <- colorRampPalette( c("blue", "green") )
# Generate the desired number of colors from this palette
nbcol <- 100
color <- jet.colors(nbcol)
# Compute the z-value at the facet centres
zfacet <- z2[-1, -1] + z2[-1, -ncz] + z2[-nrz, -1] + z2[-nrz, -ncz]
# Recode facet z-values into color indices
facetcol <- cut(zfacet, nbcol)
persp(x, y, z2, zlim=c(-8, 10.5), col = color[facetcol], phi = 30, theta = -30)
#zlim added to encompass combined ranges of z1 and z2
#comparing the values, we see that there's different, overlapping scales from z1 and z2
summary(as.vector(z1))
summary(as.vector(z2))
因此,当你看到两个z2图时,你会发现它们处于不同的尺度上。如果我能得到那个颜色范围来覆盖z1和z2的范围
那就更清楚了答案 0 :(得分:4)
您可以在切割之前连接z值的两个向量(矩阵),然后在指定颜色时参考结果(切割)向量的相关子集。
color <- jet.colors(nbcol)
z1facet <- z1[-1, -1] + z1[-1, -ncz] + z1[-nrz, -1] + z1[-nrz, -ncz]
z2facet <- z2[-1, -1] + z2[-1, -ncz] + z2[-nrz, -1] + z2[-nrz, -ncz]
facetcol <- cut(c(z1facet, z2facet), nbcol)
persp(x, y, z1, zlim=c(-8, 10.5),
col=color[facetcol[seq_along(z1facet)]],
phi=30, theta=-30)
persp(x, y, z2, zlim=c(-8, 10.5),
col=color[facetcol[-seq_along(z1facet)]],
phi=30, theta=-30)
或者,使用lattice::wireframe
,这可能更简单,特别是在处理许多表面图时:
library(lattice)
# First, create a named list of the surface matrices.
L <- list(z1=z1, z2=z2)
# Iterate over the elements of L, creating data.frames with row number,
# column number, and cell value, as well as matrix name (i.e. name of
# the element of L).
dat <- do.call(rbind, lapply(seq_along(L), function(i) {
setNames(data.frame(which(!is.na(L[[i]]), arr.ind=TRUE),
c(L[[i]]), names(L)[i]),
c('x', 'y', 'z', 'g'))
}))
# Plot with wireframe, faceting by `g` (the matrix name).
wireframe(z ~ x + y|g, data=dat, drape=TRUE, col.regions=color)
根据需要调整screen
和distance
以获得您想要的外观,例如:
wireframe(z ~ x + y|g, data=dat, drape=TRUE, col.regions=color,
screen=list(z=30, x=-60), distance=0.5)