我是Spring MVC的新手。一直试图解决这个问题一段时间(很多个小时)。
我运行此登录表单。我显示正确,但提交时显示404 Not Found。
web.xml - >
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" id="WebApp_ID" version="3.0">
<display-name>LoginApp-SpringMVC-Part1</display-name>
<welcome-file-list>
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<servlet>
<servlet-name>dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>/Login.spring</url-pattern>
</servlet-mapping>
</web-app>
dispatcher-servlet.xml - &gt;
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc.xsd
http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd">
<context:component-scan base-package="com.webform.controller" ></context:component-scan>
<bean class="org.springframework.web.servlet.view.InternalResourceViewResolver" >
<property
name="prefix"
value="/" >
</property>
<property
name="suffix"
value=".jsp" >
</property>
</bean>
</beans>
LoginController.java - &gt;
package com.webform.controller;
import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.bind.annotation.RequestParam;
import org.springframework.web.servlet.ModelAndView;
@Controller
@RequestMapping("/Login.spring")
public class LoginController {
@RequestMapping(method = RequestMethod.POST)
public ModelAndView processCredentials(@RequestParam("userName")String userName,@RequestParam("password")String password) {
String message = "Invalid credentials";
if(!userName.equals("") && !password.equals("")) {
if(userName.equals(password)) {
message = "Welcome " + userName + "!!";
}
}
return new ModelAndView("list","message",message);
}
}
index.jsp - &gt;
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
<title>Login Form</title>
</head>
<body>
<h2>Login</h2>
<form method="POST" action="Login.spring">
<table>
<tr>
<td>User Name:</td>
<td><input type="text" name="userName"></td>
</tr>
<tr>
<td>Password:</td>
<td><input type="password" name="password"></td>
</tr>
<tr>
<td colspan="2"><input type="submit" value="Submit"/></td>
</tr>
</table>
</form>
</body>
</html>
现在,如果我在web.xml中将<url-pattern>/Login.spring</url-pattern>
更改为<url-pattern>*/Login.spring</url-pattern>
,那么它会找到405找不到方法
先谢谢你。
此致
答案 0 :(得分:0)
将您的<url-pattern>/Login.spring</url-pattern>
更改为
web.xml中的<url-pattern>*.jsp</url-pattern>
首先尝试在方法级别而不是类级别进行映射,如下所示:
@RequestMapping(value="/Login.spring",method = RequestMethod.POST)
答案 1 :(得分:0)
我的问题的答案是tomcat和jdk版本。
所需的最低配置: Tomcat:v7.0 JDK:1.7.x