我的SQLite打破了我的应用程序,它说没有名为Goal的列

时间:2015-04-21 20:24:35

标签: android sqlite

我正在尝试将一组字符串变量存储到SQLite数据库中,直到我添加了另外两个名为“Weight”和“Goal”的列。不幸的是,每当我尝试编译它现在它停止工作,说明

04-21 20:19:11.675    2000-2000/com.example.wolfe_000.final_final_zeno E/SQLiteLog﹕ (1) table Registered_Info has no column named Goal

正如我在添加重量和目标之前说的那样,这里是数据库操作的代码:

公共类DatabaseOperations扩展了SQLiteOpenHelper {

public static int database_version = 1;
public String CREATE_QUERY = "CREATE TABLE "+TableData.TableInfo.TABLE_NAME + "("+TableData.TableInfo.USER_NAME+" TEXT,"+TableData.TableInfo.USER_PASS+" TEXT,"+TableData.TableInfo.USER_EMAIL+" TEXT,"+ TableData.TableInfo.USER_WEIGHT+" TEXT,"+ TableData.TableInfo.USER_GOAL+" TEXT );";


public DatabaseOperations(Context context) {
    super(context, TableData.TableInfo.DATABASE_NAME, null, database_version);
    Log.d("Database Operations", "Database Created");
}

@Override
public void onCreate(SQLiteDatabase sdb) {
    sdb.execSQL(CREATE_QUERY);
    Log.d("Database Operations", "Table Created");
    sdb.close();
}

@Override
public void onUpgrade(SQLiteDatabase arg0, int arg1, int arg2) {

}

public void putInformation(DatabaseOperations dop, String name, String pass, String email, String weight, String goal) {
    SQLiteDatabase SQ = dop.getWritableDatabase();
    ContentValues cv = new ContentValues();
    cv.put(TableData.TableInfo.USER_NAME, name);
    cv.put(TableData.TableInfo.USER_PASS, pass);
    cv.put(TableData.TableInfo.USER_EMAIL, email);
    cv.put(TableData.TableInfo.USER_WEIGHT,weight);
    cv.put(TableData.TableInfo.USER_GOAL,goal);
    long k = SQ.insert(TableData.TableInfo.TABLE_NAME, null, cv);
    Log.d("Database Operations", "One Row Inserted");
    SQ.close();
}

public Cursor getInformation(DatabaseOperations dop){
    SQLiteDatabase SQ = dop.getReadableDatabase();
    String[] columns = {TableData.TableInfo.USER_NAME, TableData.TableInfo.USER_PASS, TableData.TableInfo.USER_EMAIL, TableData.TableInfo.USER_WEIGHT, TableData.TableInfo.USER_GOAL};
    Cursor CR = SQ.query(TableData.TableInfo.TABLE_NAME, columns, null, null, null, null, null);
    return CR;
}

1 个答案:

答案 0 :(得分:0)

更改database_version = 2;或从设备中删除应用程序。

然后尝试

@Override
public void onUpgrade(SQLiteDatabase db, int oldVersion, int newVersion) {
    Log.w(NkSQLiteOpenHelper.class.getName(),
            "Upgrading database from version " + oldVersion + " to "
                    + newVersion + ", which will destroy all old data");
    db.execSQL("DROP TABLE IF EXISTS " + TABLE_NAME);
    onCreate(db);
}