我在PostgreSQL上使用Sequelize来存储属于组织的用户。组织拥有用户可以访问的设备。所以从本质上讲,用户也可以通过他们的组织拥有设备。
我将每个设备与使用organization_id的组织相关联,并且每个用户都使用organization_id与组织相关联。我正试图用Sequelize来设置它以正确阅读它。我正在尽力不去编写自定义查询,但如果我最终还是可以的话。
我正在尝试将所有设备与用户ID相关联。当我尝试运行findAll(...)命令时,Sequelize打印出这个疯狂的查询并出现错误。它输出此查询,然后输出一个空集:
SELECT
"receiver"."receiver_id" AS "id",
"receiver"."organization_id" AS "organizationID",
"receiver"."identifier",
"receiver"."secret",
"receiver"."iterations",
"receiver"."sodium",
"receiver"."algorithm",
"receiver"."created",
"receiver"."modified",
"receiver"."deleted",
"receiver"."organization_id",
"users"."user_id" AS "users.id",
"users"."password" AS "users.password",
"users"."sodium" AS "users.sodium",
"users"."email" AS "users.email",
"users"."organization_id" AS "users.organizationID",
"users"."iterations" AS "users.iterations",
"users"."algorithm" AS "users.algorithm",
"users"."created" AS "users.created",
"users"."modified" AS "users.modified",
"users"."deleted" AS "users.deleted",
"users"."organization_id" AS "users.organization_id",
"users.organizations"."created" AS "users.organizations.created",
"users.organizations"."modified" AS "users.organizations.modified",
"users.organizations"."organization_id" AS "users.organizations.organization_id"
FROM "receivers" AS "receiver"
INNER JOIN (
"organizations" AS "users.organizations"
INNER JOIN "users" AS "users"
ON "users"."user_id" = "users.organizations"."organization_id")
ON "receiver"."receiver_id" = "users.organizations"."organization_id"
AND ("users"."deleted" IS NULL AND "users"."user_id" = 2)
WHERE "receiver"."deleted" IS NULL;
如何更好地编写定义或代码?
非常感谢。
我在Sequelize中的表定义:
var organization = sequelize.define( 'organization', {
'id': {
type: Sequelize.BIGINT,
field: 'organization_id',
allowNull: false,
primaryKey: true,
autoIncrement: true
},
'name' : {
type: Sequelize.STRING( 256 ),
field: 'name',
allowNull: false,
validate: {
notEmpty: true
}
}
}, {
'createdAt' : 'created',
'updatedAt' : 'modified',
'deletedAt' : 'deleted',
'tableName' : 'organizations',
'paranoid' : true
} );
var user = sequelize.define( 'user', {
'id': {
type: Sequelize.BIGINT,
field: 'user_id',
allowNull: false,
primaryKey: true,
autoIncrement: true
},
'password': {
type: Sequelize.STRING( 64 ),
field: 'password',
allowNull: false,
validate: {
notEmpty: true
}
},
'sodium': {
type: Sequelize.STRING( 64 ),
field: 'sodium',
allowNull: false,
validate: {
notEmpty: true
}
},
'email' : {
type: Sequelize.STRING( 64 ),
field: 'email',
allowNull: false,
validate: {
notEmpty: true
}
},
'organizationID' : {
type: Sequelize.BIGINT,
field: 'organization_id',
allowNull: false,
validate: {
notEmpty: true
}
},
'iterations' : {
type: Sequelize.INTEGER,
field: 'iterations',
allowNull: false,
validate: {
notEmpty: true
}
},
'algorithm' : {
type: Sequelize.STRING( 8 ),
field: 'algorithm',
allowNull: false,
defaultValue: 'sha256'
}
}, {
'createdAt' : 'created',
'updatedAt' : 'modified',
'deletedAt' : 'deleted',
'tableName' : 'users',
'paranoid' : true
} );
var receiver = sequelize.define( 'receiver', {
'id': {
type: Sequelize.BIGINT,
field: 'receiver_id',
allowNull: false,
primaryKey: true,
autoIncrement: true
},
'organizationID': {
type: Sequelize.BIGINT,
field: 'organization_id',
allowNull: false,
validate: {
notEmpty: true
}
},
'identifier': {
type: Sequelize.STRING( 64 ),
field: 'identifier',
allowNull: false,
validate: {
notEmpty: true
}
},
'secret' : {
type: Sequelize.STRING( 64 ),
field: 'secret',
allowNull: false,
validate: {
notEmpty: true
}
},
'iterations' : {
type: Sequelize.INTEGER,
field: 'iterations',
allowNull: false,
validate: {
notEmpty: true
}
},
'sodium': {
type: Sequelize.STRING( 64 ),
field: 'sodium',
allowNull: false,
validate: {
notEmpty: true
}
},
'algorithm' : {
type: Sequelize.STRING( 8 ),
field: 'algorithm',
allowNull: false,
defaultValue: 'sha256'
}
}, {
'createdAt' : 'created',
'updatedAt' : 'modified',
'deletedAt' : 'deleted',
'tableName' : 'receivers',
'paranoid' : true
} );
// Organizations have users and users have organizations
organization.hasMany( user, { 'foreignKey' : 'organization_id' } );
user.belongsTo( organization, { 'foreignKey' : 'organization_id' } );
// Organizations have receivers
organization.hasMany( receiver, { 'foreignKey' : 'organization_id' } );
receiver.belongsTo( organization, { 'foreignKey' : 'organization_id' } );
// Receivers to users
user.belongsToMany( receiver, { 'through' : 'organizations', 'foreignKey' : 'organization_id' } );
receiver.belongsToMany( user, { 'through' : 'organizations', 'foreignKey' : 'organization_id' } );
我用来查询的代码:
// Get the devices for this person
db.receiver.findAll( {
'include' : [
{
'model' : db.user,
'where' : { 'id' : 2 }
}
]
} )
.complete( function( error, result ) {
if( error ) {
console.log( error );
}
else {
console.log( result );
}
} );
答案 0 :(得分:2)
尝试以下操作,它会选择与where语句匹配的用户,并包含与之关联的组织,其中包含与之关联的设备,因此您最终应该使用与之关联的设备用户。
// Organizations have users
user.belongsTo(organization);
// Organizations have receivers
receiver.belongsTo(organization);
// Get the devices for this person
db.user.find( {
'include' : [
{model: db.organization,
include: [model: db.receiver]
}
]
'where' : { 'id' : 2 }
} )
.complete( function( error, result ) {
if( error ) {
console.log( error );
}
else {
console.log( result );
}
} );
如果你使用下划线id字段名称,例如organization_id,你可以指定" underscored:true"在创建模型时,您不必在创建关联时指定外键字段。