找到并显示前n个自然数的立方体之和

Question

我需要找到并显示前n个自然数的立方体的总和，以及我目前使用的代码，我只能打印到我想要​​的范围。

最大值是20，它打印我的数字的立方体，最多为20个。我为总和写的循环不起作用，通常会使程序崩溃。

任何有关如何制作它的帮助或想法，以便程序只能累加到输入的数字，然后总结这些立方体将不胜感激，请保持简单。

public class MyIntNumberr
{ // construct a myintnumber with one instance field n
    public MyIntNumberr(int n)
    {
        number = n;
    }

    public void calcCubeAndSum(int num)
    {

        if (num < 0)
        {
            System.out.println("that integer is invalid please try again");
            System.exit(0);
        }
        while (num >= 1 && num <= 20)
        {
            System.out.println(" " + num + "      " + Math.pow(num, 3));
            num = num + 1;
        }

    }

    // instance fields
    private int number;
}


import javax.swing.JOptionPane;

public class MyIntNumberTestt
{
    public static void main(String[] args)
    {
        int number, num;

        String input = JOptionPane.showInputDialog("enter a value to cube and gather  the sum of");
        num = Integer.parseInt(input);

        MyIntNumberr richard = new MyIntNumberr(num);

        richard.calcCubeAndSum(num);

        System.exit(0);
    }
}

Answer 1

我没有在你的代码中看到你累积多维数据集的总和......

static Scanner input = new Scanner(System.in);

public static void main(String[] args) throws Exception {    
    System.out.print("Enter a value to cube and gather the sum of: ");
    int num = input.nextInt();
    calcCubeAndSum(num);
}

private static void calcCubeAndSum(int num) {
    if (1 <= num && num <= 20) {
        int sum = 0;
        while (num <= 20) {
            // Calculate the cube
            int cube = num * num * num;

            // Accumulate the cube into a sum
            sum += cube;

            // Display current result
            System.out.println("Current number: " + num + "\tCubed: " + cube + "\tCurrent Sum: " + sum);

            // Go to the next number
            num++;
        }
        // Display Total Sum
        System.out.println("Total Sum: " + sum);
    } else {
        System.out.println("That integer is invalid please try again");
    }
}

结果：

Answer 2

使用PYTHON可以轻松找到N个自然数 希望大家都喜欢。...

using System;
using System.Collections;
using System.Collections.Generic;
using UnityEngine;

public class ScriptFader : MonoBehaviour
{
    // attached game object for fading
    public GameObject Sphere;

    // fade speed length
    public float fadeSpeed;

    //Pause length between fades
    public int fadePause;

    void Awake()
    {
        StartCoroutine(FadeOut(fadeSpeed));
    }


    //Fade Out Coroutine
    public IEnumerator FadeOut(float fadeSpeed)
    {
        Renderer rend = Sphere.transform.GetComponent<Renderer>();
        Color matColor = rend.material.color;
        float alphaValue = rend.material.color.a;


        //while loop to deincrement Alpha value until object is invisible
        while (rend.material.color.a > 0f)
        {
            alphaValue -= Time.deltaTime / fadeSpeed;
            rend.material.color = new Color(matColor.r, matColor.g, matColor.b, alphaValue);
            yield return new WaitForSeconds(fadePause);
        }
        rend.material.color = new Color(matColor.r, matColor.g, matColor.b, 0f);
        StartCoroutine(FadeIn(fadeSpeed));
    }

    //Fade In Coroutine
    public IEnumerator FadeIn(float fadeSpeed)
    {
        //waits for the return value of FadeOut coroutine to commence
        yield return FadeOut;

        Renderer rend = Sphere.transform.GetComponent<Renderer>();
        Color matColor = rend.material.color;
        float alphaValue = rend.material.color.a;


        //while loop to increment object Alpha value until object is opaque
        while(rend.material.color.a < 1f)
        {
            alphaValue += Time.deltaTime / fadeSpeed;
            rend.material.color = new Color(matColor.r, matColor.g, matColor.b, alphaValue);
            yield return null;
        }
        rend.material.color = new Color(matColor.r, matColor.g, matColor.b, 1f);
        StartCoroutine(FadeOut(fadeSpeed));
    }
}

答案

n = int(input("Enter the value of n:"))
for i in range (1,n+1):
    print(i)