Question

我想使用php和mysqli在一个表单中添加多个记录。这是我的代码在我的php页面的开头我在这里包含了数据库连接代码我附加了代码来插入数据但是我提交的按钮数据不会插入到表中。任何人都可以帮我解决这个问题吗？

$test='TN000006-1,TN000006-2,TN000006-3,TN000006-4' ;
$numberChunks = explode(",", $test);

echo "First chunk = $numberChunks[0]<br />";
$insertbookcopy="insert into bookcopy('bookcopNo')values";
for($i=0;$i<$copy;$i++){
    echo  $numberChunks[$i];
    $insertbookcopy .="('$numberChunks[$i]',$titleNo)";
}

Answer 1

这有帮助吗？

$test='TN000006-1,TN000006-2,TN000006-3,TN000006-4';
$numberChunks = explode(",", $test);
$copy = count($numberChunks); //not sure why you called it copy though

for($i=0;$i<$copy;$i++)
{
$insertbookcopy = "insert into bookcopy ('bookcopNo') values ('".$numberChunks[$i]."');";
echo $insertbookcopy;
echo "<br>";
$result = mysql_query($insertbookcopy);

}

如何使用PHP和Mysqli将多个记录插入表中？

1 个答案: