Question

我有一个查询返回数千个带有联系信息的数组。每个都有一个与之关联的用户ID（IndvID）。我需要将具有匹配用户ID的数组连接到多维数组中。

所以这个：

Array
(
    [EmailID] => 1
    [IndvID] => 78
    [EmailType] => Business
    [Preferred] => false
    [Email] => theiremail@something.com
    [Listed] => true
    [!diffgr:id] => dbs71
    [!msdata:rowOrder] => 0
)
Array
(
    [EmailID] => 2
    [IndvID] => 78
    [EmailType] => Personal
    [Preferred] => true
    [Email] => theiremail@something.com
    [Listed] => true
    [!diffgr:id] => dbs72
    [!msdata:rowOrder] => 1
)
Array
(
    [EmailID] => 3
    [IndvID] => 85
    [EmailType] => Personal
    [Preferred] => true
    [Email] => theiremail@something.com
    [Listed] => true
    [!diffgr:id] => dbs73
    [!msdata:rowOrder] => 2
)
Array
(
    [EmailID] => 4
    [IndvID] => 86
    [EmailType] => Personal
    [Preferred] => true
    [Email] => theiremail@something.com
    [Listed] => true
    [!diffgr:id] => dbs74
    [!msdata:rowOrder] => 3
)

变为

   array[0](   
        Array[0]
        (
            [EmailID] => 1
            [IndvID] => 78
            [EmailType] => Business
            [Preferred] => false
            [Email] => theiremail@something.com
            [Listed] => true
            [!diffgr:id] => dbs71
            [!msdata:rowOrder] => 0
        )
        Array[1]
        (
            [EmailID] => 2
            [IndvID] => 78
            [EmailType] => Personal
            [Preferred] => true
            [Email] => theiremail@something.com
            [Listed] => true
            [!diffgr:id] => dbs72
            [!msdata:rowOrder] => 1
        )
    )
        Array[1]
        (
            [EmailID] => 3
            [IndvID] => 85
            [EmailType] => Personal
            [Preferred] => true
            [Email] => theiremail@something.com
            [Listed] => true
            [!diffgr:id] => dbs73
            [!msdata:rowOrder] => 2
        )
        Array[2]
        (
            [EmailID] => 4
            [IndvID] => 86
            [EmailType] => Personal
            [Preferred] => true
            [Email] => theiremail@something.com
            [Listed] => true
            [!diffgr:id] => dbs74
            [!msdata:rowOrder] => 3
        )

与＆＃34; IndvID＆＃34;

相互匹配

Answer 1

这是一种方式。使用值IndvID作为键创建结果，然后使用子数组。如果要重新排序主索引，请使用array_values：

$result = array();

foreach($array as $values) {
    $result[$values['IndvID']][] = $values;
}
// if you want to reset the keys
$result = array_values($result);

Answer 2

非常直接的做法，我已经将聚合数组的关键字设为IndvID，以使事情变得更简单，如果不行，请告诉我，我会调整答案

function add_to_array(array $array, & $aggregated_array)
{
    if ( ! isset($array['IndvID']))
        return false;

    $aggregated_array[$array['IndvID']][] = $array;
}

$aggregated_array = array();
// Run query here...
// I'm assuming mysqli here as it's what I mostly use, substitute as necessary
while ($row = $result->fetch_assoc()) 
{
    add_to_array($row, $aggregated_array);
}

print_r($aggregated_array);

在PHP中加入多维数组

2 个答案: