Question

我有许多名称的XML，如列表：

<apelidos>
    <apelido>Casmilo</apelido>
    <apelido>Castro</apelido>
</apelidos>

我做了这样的模型：

namespace IdCel.Model
{
   [XmlTypeAttribute(AnonymousType = true)]
   public class apelidos
   {
       [XmlArray("apelidos")]
       [XmlArrayItem("apelidos")]
       public List<apelido> apelidosNomes { get; set; }

       public apelidos()
       {
           apelidosNomes = new List<apelido>();
       }
   }

   public class apelido
   {
       [XmlElement(ElementName = "apelido")]
       public string apelidoNome { get; set; }
   }
}

我的XmlSerializer

HttpWebRequest request = WebRequest.Create(uri) as HttpWebRequest;
XmlSerializer ser = new XmlSerializer(objetoLista.GetType());

WebResponse response = request.GetResponse();
var result = ser.Deserialize(response.GetResponseStream());

return result;

但它不起作用，我使用没有列表的XML执行相同的代码并且它工作正常

Answer 1

如果您只需阅读apelido代码的内容，则在使用Linq To XML时速度会更快。例如：

var xml = @"<apelidos>
                <apelido>Casmilo</apelido>
                <apelido>Castro</apelido>
            </apelidos>";

var doc = XDocument.Parse(xml);
var apelidos = from apelido in doc.Descendants("apelido")
               select apelido.Value;

这会为您提供一个包含所有名称的IEnumerable<string>。

编辑：要从Web加载XML，您可以执行以下操作：

HttpWebRequest request = WebRequest.Create(uri) as HttpWebRequest;

WebResponse response = request.GetResponse();
var doc = XDocument.Load(response.GetResponseStream());

Answer 2

现在它奏效了！我这样做了：

[Serializable()]
public class apelidos
{
    [System.Xml.Serialization.XmlElement("apelido")]
    public List<string> apelido { get; set; }
}

而且：

HttpWebRequest request = WebRequest.Create(uri)
           as HttpWebRequest;

        XmlSerializer ser = new XmlSerializer(objetoLista.GetType());

        WebResponse response = request.GetResponse();
        var result = ser.Deserialize(response.GetResponseStream());

        return result;

XmlSerializer WebResponse

2 个答案: