Question

编写一个程序，提示用户输入两个long值。实现一个名为negative_count()的函数，该函数接受数据类型为long的两个参数，并返回一个整数，该整数是负数的参数个数。然后函数main()显示结果例如：

输入数据类型的两个整数＆＃34; long＆＃34;：-1264364007 -2012334695
输入的负数为2

#include <stdio.h>
#include <stdlib.h>

 /*
 * 
 */
 long num1,num2;
 void Negative_Count(long int,long int);
  int main(void) {


     printf("Enter two number: ");
     scanf("%ld%ld",&num1,num2);
     ("you entered %ld%ld",&num1,&num2);

     Negative_Count(num1,num2);


    return (0);
}

 void Negative_Count(long int num1,long int num2)
 {
       if (num1,num2<0)      
       printf("%ld%ld is negative.",&num1,&num2);
    else if (num1,num2>0)   
      printf("%ld%ld is positive.",&num1,&num2);
    else if (num1>0, num2<0)
            printf("%ld is negative",&num2);
    else if (num1<0, num2>0)
        printf("%ld is negative",&num1);



 }

我可以使用带有两个变量的循环吗？

Answer 1

scanf("%ld%ld",&num1,num2);

应该是

scanf("%ld%ld", &num1, &num2);

("you entered %ld%ld",&num1,&num2);

应该是

printf("you entered %ld %ld", num1, num2);

  if (num1,num2<0)      
   printf("%ld%ld is negative.",&num1,&num2);
else if (num1,num2>0)   
  printf("%ld%ld is positive.",&num1,&num2);
else if (num1>0, num2<0)
        printf("%ld is negative",&num2);
else if (num1<0, num2>0)
    printf("%ld is negative",&num1);

应该是

if (num1 < 0 && num2 < 0)   
    printf("%ld and %ld are negative.", num1, num2);
else if (num1 > 0 && num2 > 0)   
    printf("%ld and %ld are positive.", num1, num2);
else if (num1 > 0 && num2 < 0)
    printf("%ld is negative", num2);
else if (num1 < 0 && num2 > 0)
    printf("%ld is negative", num1);

使用和运算符（&&）：如果两个操作数均为非零，则条件为真。

请注意printf（与scanf相对）并不需要变量的地址，只需传递值。

Answer 2

您的 scanf 和 printf 格式存在问题。 if语句中的条件检查也是错误的。

您可以修改以下代码，以便正常工作......

#include <stdio.h>
#include <stdlib.h>

 void Negative_Count(long int,long int);

  int main(void) {

    long num1,num2;

    printf("Enter two number: ");
    scanf("%ld%ld",&num1,&num2);
    printf("you entered %ld%ld \n",num1,num2);

    Negative_Count(num1,num2);

    return 0;

}

 void Negative_Count(long int num1,long int num2)
 {
       if (num1<0 && num2<0) {     
        printf("%ld , %ld are negative.",num1,num2);
       }
       else if (num1>0 && num2>0) { 
        printf("%ld , %ld are positive.",num1,num2);
       }
       else if (num1>0 && num2<0){
        printf("%ld is negative",num2);
       }
       else if (num1<0 && num2>0){
        printf("%ld is negative",num1);
       }
 }

创建一个功能

2 个答案: