Question

我有这么多长数据库，所以我在逗号中使用seq_no在单列中使用多个序列存储，但现在我想在一列中使用所有序列，所以我很困惑如何创建这个sql结果这个。

例如：

TABLE STRUCTURE 
SR_NO IS INT ,
SEQ_NO IS VARCHAR(MAX)

SR_NO   SEQ_NO
---------------------------------    
  1     1839073,
  2     1850097,1850098,
  3     1850099,1850100,1850110

我需要得到这个结果：

SEQ_NO 
--------------
1839073
1850097
1850098
1850099
1850100
1850110

谢谢！

Answer 1

declare @t table(Id int,seq varchar(100)) 
insert into @t (Id,seq) values (1,'1839073,'),(2,'1839073,1850098,'),(3,'1850099,1850100,1850110 ')



;With Cte as (
SELECT A.Id,  
     Split.a.value('.', 'VARCHAR(100)') AS Seq  
 FROM  
 (
     SELECT Id,  
         CAST ('<M>' + REPLACE(seq, ',', '</M><M>') + '</M>' AS XML) AS Data  
     FROM  @t
 ) AS A CROSS APPLY Data.nodes ('/M') AS Split(a) )

 Select ID,Seq from Cte Where Seq > ''

Answer 2

尝试将其与XML分开

SELECT SR_NO, t.c.value('.', 'VARCHAR(2000)') COL1
FROM (
  SELECT SR_NO, x = CAST('<t>' + 
        REPLACE(SEQ_NO, ',', '</t><t>') + '</t>' AS XML) 
        FROM 
       (values(1,'1839073'),(2, '1850097,1850098'),
        (3, '1850099,1850100,1850110')) y(SR_NO, SEQ_NO)

) a
CROSS APPLY x.nodes('/t') t(c)

结果：

SR_NO  COL1
1      1839073
2      1850097
2      1850098
3      1850099
3      1850100
3      1850110

您可以将其替换为您的表格：

 (values (1,'1839073'),(2, '1850097,1850098'),
  (3, '1850099,1850100,1850110')) y(SR_NO, SEQ_NO)

Answer 3

这应该这样做:(用你的表名替换YourTableName）

;WITH CTE(NEW_SEQ_NO, SEQ_NO) as (
SELECT LEFT(SEQ_NO, CHARINDEX(',',SEQ_NO + ',') -1),
    STUFF(SEQ_NO, 1, CHARINDEX(',',SEQ_NO + ','), '')
FROM YourTableName
WHERE SEQ_NO <> '' AND SEQ_NO IS NOT NULL 
UNION all
SELECT LEFT(SEQ_NO, CHARINDEX(',',SEQ_NO + ',') -1),
    STUFF(SEQ_NO, 1, CHARINDEX(',',SEQ_NO + ','), '')
FROM CTE
WHERE SEQ_NO <> '' AND SEQ_NO IS NOT NULL 
)

SELECT NEW_SEQ_NO from CTE ORDER BY NEW_SEQ_NO

您可以查看此主题以获取更多信息： Turning a Comma Separated string into individual rows

Answer 4

在引用Turning a Comma Separated string into individual rows

后，我写了以下查询

它适用于你

create table STRUCTURE(SR_NO int, SEQ_NO varchar(max))
insert STRUCTURE select 1, '1839073,'
insert STRUCTURE select 2, '1850097,1850098,'
insert STRUCTURE select 3, '1850099,1850100,1850110'


;with tmp(SR_NO, DataItem, SEQ_NO) as (
select SR_NO, LEFT(SEQ_NO, CHARINDEX(',',SEQ_NO+',')-1),
STUFF(SEQ_NO, 1, CHARINDEX(',',SEQ_NO+','), '')
from STRUCTURE
union all
select SR_NO, LEFT(SEQ_NO, CHARINDEX(',',SEQ_NO+',')-1),
STUFF(SEQ_NO, 1, CHARINDEX(',',SEQ_NO+','), '')
from tmp
where SEQ_NO > ''
)

Select DataItem as  SEQ_NO from tmp order by SEQ_NO;

如何为此结果编写SQL查询？

4 个答案: