Question

我的json有问题，我使用PHP Curl发布带有表单数据的文件，并在发布后回滚一些奇怪的json

像这样

{"code":200,"status":"Success","badges":{"id":"0d28f02d13fe4c7ca8681e2ed0224180","name":"test 5","description":"test 5","image":"http://somesite.id/images/d25273bdc1b54525a602dfca8ab826fdtest.jpg","category":"Upload","target":2}}

问题是，返回的结果不能是json_decode，我知道如果这个json很奇怪，我可以打印但不能是json_decode，

我无法访问更改API，我需要来自徽章的ID，有什么诀窍吗？或者获取id的方法，或者一些修改后的返回结果可以解码

我试过了

$a = 'that result';
$b = "'".$a."'";

$c = json_decode($b);

但它仍然是json格式，而不是成为数组需要一些想法和帮助，thx

编辑：

让我们说

$result =     {"code":200,"status":"Success","badges":{"id":"0d28f02d13fe4c7ca8681e2ed0224180","name":"test 5","description":"test 5","image":"http://somesite.id/images/d25273bdc1b54525a602dfca8ab826fdtest.jpg","category":"Upload","target":2}}

when I json_decode

$data = json_decode($result);
var_dump($result );
print_r($data);

它会返回

{"code":200,"status":"Success","badges":{"id":"0d28f02d13fe4c7ca8681e2ed0224180","name":"test 5","description":"test 5","image":"http://somesite.id/images/d25273bdc1b54525a602dfca8ab826fdtest.jpg","category":"Upload","target":2}}bool(true) 1

Answer 1

试试这个

$js='{"code":200,"status":"Success","badges":{"id":"0d28f02d13fe4c7ca8681e2ed0224180","name":"test 5","description":"test 5","image":"http://somesite.id/images/d25273bdc1b54525a602dfca8ab826fdtest.jpg","category":"Upload","target":2}}';
var_dump(json_decode($js,true));

您的输出将是

array (size=3)
  'code' => int 200
  'status' => string 'Success' (length=7)
  'badges' => 
    array (size=6)
      'id' => string '0d28f02d13fe4c7ca8681e2ed0224180' (length=32)
      'name' => string 'test 5' (length=6)
      'description' => string 'test 5' (length=6)
      'image' => string 'http://somesite.id/images/d25273bdc1b54525a602dfca8ab826fdtest.jpg' (length=66)
      'category' => string 'Upload' (length=6)
      'target' => int 2

Answer 2

您不希望在字符串周围加上引号。变化

$a = 'that result';
$b = "'".$a."'";

$c = json_decode($b);

简单地

$a = 'that result';
$c = json_decode($a);

JSON有效。将引号括起来使无效。

Answer 3

原始响应是正确的JSON语法。请勿在{{1}}

中添加额外的引号

而是尝试这个，作为一个例子：

$b = "'".$a."'"; //INCORRECT

哪个会打印：

/* $response is the result from API */
$response = '{"code":200,"status":"Success","badges":{"id":"0d28f02d13fe4c7ca8681e2ed0224180"}}';
$decoded = json_decode($response);
print_r($decoded); //See full decoded
$badge_id = $decoded->badges->id;
echo "The badge id is $badge_id \n";

json无法解码

3 个答案: