我正在尝试进行OTH应用程序而且我收到此错误
发生数据库错误
错误号码:1054
'字段列表'中的未知列'数据'
SELECT
data
FROMci_sessions
WHEREid
= 'dd8fddaabb45c365fbf27a6fdc5ea60d59f569e4'和ip_address
=':: 1'文件名:libraries / Session / drivers / Session_database_driver.php
行号:160
这是Session_database_driver.php
public function read($session_id) {
if ($this->_get_lock($session_id) !== FALSE)
{
// Needed by write() to detect session_regenerate_id() calls
$this->_session_id = $session_id;
$this->_db
->select('data')
->from($this->_config['save_path'])
->where('id', $session_id);
if ($this->_config['match_ip'])
{
$this->_db->where('ip_address', $_SERVER['REMOTE_ADDR']);
}
if (($result = $this->_db->get()->row()) === NULL)
{
$this->_fingerprint = md5('');
return '';
}
// PostgreSQL's variant of a BLOB datatype is Bytea, which is a
// PITA to work with, so we use base64-encoded data in a TEXT
// field instead.
$result = ($this->_platform === 'postgre')
? base64_decode(rtrim($result->data))
: $result->data;
$this->_fingerprint = md5($result);
$this->_row_exists = TRUE;
return $result;
}
$this->_fingerprint = md5('');
return '';
}
答案 0 :(得分:3)
根据CI手册关于Sessions
的基本格式
ci_sessions
表的格式是:
CREATE TABLE IF NOT EXISTS `ci_sessions` (
session_id varchar(40) DEFAULT '0' NOT NULL,
ip_address varchar(45) DEFAULT '0' NOT NULL,
user_agent varchar(120) NOT NULL,
last_activity int(10) unsigned DEFAULT 0 NOT NULL,
user_data text NOT NULL,
PRIMARY KEY (session_id),
KEY `last_activity_idx` (`last_activity`)
);
在您的PHP代码中,您使用了不同的字段:
$this->_db
->select('data')
->from($this->_config['save_path'])
->where('id', $session_id);
因此,通过将代码更改为:
$this->_db
->select('user_data')
->from($this->_config['save_path'])
->where('session_id', $session_id);
您的代码应该有效。
答案 1 :(得分:2)
我认为正确的解决方案是检查您的数据库是否正确创建。
根据Documentation for CI 3.0.0,正确的数据库将是:
CREATE TABLE IF NOT EXISTS `ci_sessions` (
`id` varchar(40) NOT NULL,
`ip_address` varchar(45) NOT NULL,
`timestamp` int(10) unsigned DEFAULT 0 NOT NULL,
`data` blob NOT NULL,
PRIMARY KEY (id),
KEY `ci_sessions_timestamp` (`timestamp`)
);
我不同意更改CI驱动程序文件