Question

我需要在函数add()中为'地址簿'添加名称和地址，然后将其写入文件。这似乎工作正常，但是，它继续循环输入名称和地址没有任何意义。我需要它在添加联系人后返回main()。

address={}

def add():
    name=input('Enter the full name of the contact you would like to add:')
    n_address=input('Enter the contacts address:')

    if name not in address:
        address[n_address]=name
        writeFile()
    else:
        print('That name has already been entered.')

    return address

def find():
    name=input('Enter the name of the contact you would like the address for:')

    if name in address:
        n_address=address.get(name)
        print(n_address)
    else:
        no=input('That name is not in the address book yet, would you like to add it? y/n:')
        if no != 'n':
            add()

def a_print():
    if ('AddressBook.txt'):
        read_file=open('AddressBook.txt','r')
        mylist=read_file.readlines()

    for line in mylist:
        if line != '\n':
            n_address, name = line.split(':')
            name = name.rstrip()
            address[n_address]=name

    return address
    print(address)

def readFile():
    pass

def writeFile():
    write_file=open('AddressBook.txt','w')

    for (k,v) in address.items():
        string=k+':'+v+'\n'
        write_file.write(string)

    write_file.close()

def main():
    print('           Personal Address Book')

    print('0 - Quit\n'
          '1 - Add a New Contact\n'
          '2 - Find Contacts Address\n'
          '3 - Print Entire Collection\n')

    choice=input('\n Choose a number corrosponding to the option above.\n')

    while choice != '0':
        if choice == '1':
            add()
        elif choice == '2':
            find()
        elif choice == '3':
            a_print()

main()

Answer 1

你需要以某种方式取消选择。选择从不重置，你陷入了while循环。将提示逻辑放在循环中，它应该可以解决您的问题：

choice = 1 # This will get reset, anything but 0 is fine.

while choice != '0':
  print('0 - Quit\n'
  '1 - Add a New Contact\n'
  '2 - Find Contacts Address\n'
  '3 - Print Entire Collection\n')
  choice=input('\n Choose a number corrosponding to the option above.\n')
  if choice == '1':
      add()
  elif choice == '2':
      find()
  elif choice == '3':
      a_print()

Answer 2

您的选择不在while循环中。选择是在循环之前进行的，然后进行。一旦进入循环，你就没有机制要求另一个选择，所以选择总是保持为添加。在循环结束之前，你需要一个新的选择：

print('0 - Quit\n'
      '1 - Add a New Contact\n'
      '2 - Find Contacts Address\n'
      '3 - Print Entire Collection\n')

choice=input('\n Choose a number corrosponding to the option above.\n')

while choice != '0':
    if choice == '1':
        add()
    elif choice == '2':
        find()
    elif choice == '3':
        a_print()
    print('0 - Quit\n'
          '1 - Add a New Contact\n'
          '2 - Find Contacts Address\n'
          '3 - Print Entire Collection\n')
    choice=input('\n Choose a number corrosponding to the option above.\n')

Answer 3

将菜单放在while循环中

def main():

    print('           Personal Address Book')


    while True:

        print('0 - Quit\n'
          '1 - Add a New Contact\n'
          '2 - Find Contacts Address\n'
          '3 - Print Entire Collection\n')

        choice=input('\n Choose a number corrosponding to the option above.\n')

        if choice == '0':
            break
        elif choice == '1':
            add()
        elif choice == '2':
            find()
        elif choice == '3':
            a_print()

Answer 4

您应该将菜单移到while choice != '0':循环内。

choice = '1'
while choice != '0':

    print('0 - Quit\n'
      '1 - Add a New Contact\n'
      '2 - Find Contacts Address\n'
      '3 - Print Entire Collection\n')

    choice=input('\n Choose a number corrosponding to the option above.\n')

    if choice == '1':

        add()

    elif choice == '2':

        find()

    elif choice == '3':

        a_print()

这样就不会让用户首先选择循环，并会提示他们选择其他选项。

我在python中的函数是循环的吗？

4 个答案: