Question

原谅天真的本性，但我正在努力解决SwiftyJSON示例项目以满足我的需求。现在，我有一个带有以下内容的AppDelegate文件;

 import UIKit
 import SwiftyJSON

 @UIApplicationMainclass AppDelegate: UIResponder, UIApplicationDelegate {

var window: UIWindow?

func application(application: UIApplication, didFinishLaunchingWithOptions launchOptions: [NSObject: AnyObject]?) -> Bool {

    let navigationController = self.window?.rootViewController as! UINavigationController
    let viewController = navigationController.topViewController as! ViewController

    let url = NSURL(string: "http://myurl/json/")
    let request = NSURLRequest(URL: url!)
    NSURLConnection.sendAsynchronousRequest(request, queue: NSOperationQueue.mainQueue(), completionHandler: {(response: NSURLResponse!, data: NSData!, error: NSError!) -> Void in
        if error == nil {
            let json = JSON(data: data!)

            for (key, subJson) in json {
                if let userName = subJson["userName"].string {
                    println(userName)
                }
            }

            viewController.json = json
        }
        else {
            println("Error: \(error.localizedDescription)")
        }
    })

    return true
    }
}

这似乎非常成功地打印了＆＃34; userName＆＃34;我运行应用程序时的字段。我现在正在试图解决如何通过我的＆＃34; userName＆＃34;数据到我的ViewController文件，并在我的单元格中显示为textLabel。尽管我付出了努力，但我只能将单元格标记为＆＃34; null，＆＃34;让我相信，我的AppDelegate中正在解析的内容无法从ViewController文件中访问。听起来不错吗？

提前致谢！

Answer 1

请尝试以下列方式访问您想要的UIViewController：

func application(application: UIApplication, didFinishLaunchingWithOptions launchOptions: [NSObject :AnyObject]?) -> Bool {

    self.window = UIWindow(frame: UIScreen.mainScreen().bounds)
    var storyboard = UIStoryboard(name: "Main", bundle: nil)

    // You need to cast to the name of your ViewController to acces to its fields after.
    var initialViewController = storyboard.instantiateViewControllerWithIdentifier("ViewController") as! ViewController

    // set the JSON value to the ViewController here.        
    initialViewController.json = json

    self.window?.rootViewController = initialViewController
    self.window?.makeKeyAndVisible()
}

您必须在Interface Builder中为所需的UIViewController设置 Storyboard ID 。通过上述方式，您可以确保保留引用，将UIViewController设置为rootViewController。

我希望这对你有所帮助。

使用SwiftyJSON解析JSON字段

1 个答案: