如何使用Printwriter将字符串数组写入java中的文本文件?

时间:2015-04-20 14:29:09

标签: java arrays string file text

我需要帮助使用Printwriter将一些数组对象的内容(以下是我正在使用的两个数组示例)写入文本文件。有任何想法吗?我是初学者,所以越简单越好,谢谢!

Astronauts[0][0] = new Passengers(-1, "", 1, 0, 0, "", "", 0, "", "", "", "", ""); 

Astronauts[0][1] = new Passengers(0, "Pilot", 2424, 14, 0, "Bruce", "Banner", 0, "678-884-6325", "Mom", "678-884-6323","","");

Astronauts[0][2] = new Passengers(0, "Pilot", 1248, 3, 0, "Sally", "Forth", 0, "678-921-1135", "Hannah", "678-921-1130","","");


 Astronauts[1][0] = new Passengers(-1, "", 2, 0, 0, "", "", 0, "", "", "", "", "");

Astronauts[1][1] = new Passengers(0, "Pilot", 1022, 55, 0, "Buz", "Aldrin", 0, "404-014-4553", "June", "404-014-4555","","");

Astronauts[1][2] = new Passengers(0, "Pilot", 2813, 8, 0, "Alice", "Dyer", 0, "678-884-6325", "Mom", "678-884-6323","","");

4 个答案:

答案 0 :(得分:2)

我不确定我是否正确捕捉到您的问题,因为将数组内容写入文件非常简单:

String[] arr = {"a", "b", "c"};
try {
    PrintWriter pw = new PrintWriter(new FileWriter("output.txt"));
    pw.println(Arrays.toString(arr));
    pw.flush();
    System.out.println("Finished");
} catch (IOException e) {
    e.printStackTrace();
}

<强> [编辑]

我意识到我可能没有解决你的整个问题。如果您想知道如何编写数组中包含的对象的所需特征,您可以覆盖自定义类的toString()方法:

class A {
    public static void main(String[] args) {
        B[] bs = {new B("a", "b"),
                  new B("c", "d"),
                  new B("e", "f"),
                  new B("g", "h")};

        try {
            PrintWriter pw = new PrintWriter(new FileWriter("output.txt"));
            for (B b : bs) {
                pw.println(b);
            }
            pw.flush();
        } catch (IOException e) {
            e.printStackTrace();
        }
        System.out.println("Finished");
    }
}

class B {
    private String prop1;
    private String prop2;

    public B (String prop1, String prop2) {
        this.prop1 = prop1;
        this.prop2 = prop2;
    }

    @Override
    public String toString() {
        return this.prop1 + " " + this.prop2;
    }
}

答案 1 :(得分:0)

PrintWriter允许String,因此您可以覆盖toString()类中的Astronauts方法,然后迭代1-D或2-D维的数组:

顺便说一下,变量名应该以小写字符开头。

  • 1-d

    for (int i = 0; i < astronauts.length; i++) { 
        pw.print(Arrays.toString(astronauts[i]); 
    } 
    
  • 2-d

    for (int i = 0; i < astronauts.length; i++) {
        for (int j = 0; j < astronauts[i].length; i++) {
            pw.print(astronauts[i][j]); 
        } 
    } 
    

别忘了flush()close() PrintWriter

答案 2 :(得分:0)

以下是您可能想要的方式。

String twoDArray[][] = {{"one","two"},{"one","two"},{"one","two"}};
    String filePath = "C:/Users/arjun.lajpal/Desktop/dummyFile.txt";
    PrintWriter writer = null;
    try {
        writer = new PrintWriter(filePath);
    } catch (FileNotFoundException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }

    writer.printf("%20s%20s","Astraunauts","Passengers");
    writer.println();
    for(int i=0;i<twoDArray.length;i++){
        for(int j=0;j<twoDArray[i].length;j++)
            writer.printf("%20s",twoDArray[i][j]);

        writer.println();

        }
    writer.flush();
    writer.close();

这不仅可以生成您的文件,还可以以漂亮的表格格式写入文件,而无需覆盖toString()方法。

答案 3 :(得分:0)

由于您的数组内容属于同一个类Passengers,如果您对默认的Array.toString格式不满意,我会在{{{{{}}中创建一个toString()方法1}}返回所需的字符串表示。

然后:

Passengers

注意:正如其他人所提到的,我将try { PrintWriter printWriter = new PrintWriter(new FileWriter("output.txt")); for(Passengers[] passengers: Astronauts) { for(Passengers passenger: passengers) { printWriter.println(passenger); } } printWriter.close(); // no need to flush, since close() does it anyway. } catch (IOException e) { e.printStackTrace(); } 变量重命名为小写Astronauts。我还将astronauts课程重命名为Passengers

编辑:使用上面的代码,输出文件应出现在运行程序的工作目录中。或者,您可以提供完整的文件路径,例如Passenger,但在这种情况下,您需要确保目录路径已存在。

另一种方法是修改代码以自动为您创建路径:

C:/Users/Me/directory/output.txt