我知道这个问题有很多相关资源。但是,我还需要一个完美的解决方案。
我动态生成了五个单选按钮组。每组最多可容纳五个单选按钮。我已经验证了“没有签到”和“至少有一个签到的功能”作为一个单独的群组。
我的问题是,如何验证“是否已检查所有群组”
表示参考:
我的代码下面:
var names = [];
$('input[type="radio"]').each(function() {
// Creates an array with the names of all the different checkbox group.
names[$(this).attr('name')] = true;
});
// Goes through all the names and make sure there's at least one checked.
for (name in names) {
var radio_buttons = $("input[name='" + name + "']");
if (radio_buttons.filter(':checked').length == 0) {
alert('none checked in ' + name);
}
else{
// At least one checked
var val = radio_buttons.val();
}
}
检查完所有单选按钮组后,我需要重定向到其他页面。它有点简单。但是,对我来说看起来很复杂。
请帮助。
更新 我为前两个组生成了HTML。
<div class="row">
<div class="optionsContainer"><div id="ratingContainer">
<ul class="0">
<li onclick="checkThis(this);"><div class="ui-radio"><input type="radio" value="Strongly disagree" name="0" id="1"></div></li>
<li onclick="checkThis(this);"><div class="ui-radio"><input type="radio" value="Disagree" name="0" id="2"></div></li>
<li onclick="checkThis(this);"><div class="ui-radio"><input type="radio" value="Neutral" name="0" id="3"></div></li>
<li onclick="checkThis(this);"><div class="ui-radio"><input type="radio" value="Agree" name="0" id="4"></div></li>
<li onclick="checkThis(this);"><div class="ui-radio"><input type="radio" value="Strongly agree" name="0" id="5"></div></li>
</ul></div></div></div>
<div class="row">
<div class="optionsContainer"><div id="ratingContainer">
<ul class="0">
<li onclick="checkThis(this);"><div class="ui-radio"><input type="radio" value="Strongly disagree" name="1" id="1"></div></li>
<li onclick="checkThis(this);"><div class="ui-radio"><input type="radio" value="Disagree" name="1" id="2"></div></li>
<li onclick="checkThis(this);"><div class="ui-radio"><input type="radio" value="Neutral" name="1" id="3"></div></li>
<li onclick="checkThis(this);"><div class="ui-radio"><input type="radio" value="Agree" name="1" id="4"></div></li>
<li onclick="checkThis(this);"><div class="ui-radio"><input type="radio" value="Strongly agree" name="1" id="5"></div></li>
</ul></div></div></div>
注意:此处仅更改组名称。
答案 0 :(得分:2)
已更改
<div id="ratingContainer">
到
<div class="ratingContainer">
。
已移除
onclick="checkThis(this);"
来自html,为所有输入元素添加了一个事件处理程序
elems.find("input").on("change", checkThis);
尝试
var allChecked = false;
var names = [];
var elems = $(".0");
function checkThis(e) {
var name = e.target.name;
if (names.length < elems.length) {
names.push(name);
};
allChecked = elems.get().every(function(el, i) {
return $(el).find(":checked").is("*")
});
alert(name + " checked");
if (allChecked) {
// do stuff
alert(names.join(" and ") + " checked, " + "allChecked:" + allChecked);
};
};
elems.find("input").on("change", checkThis);
&#13;
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<div class="row">
<div class="optionsContainer">
<div class="ratingContainer">
<ul class="0">
<li>
<div class="ui-radio">
<input type="radio" value="Strongly disagree" name="0" id="1">
</div>
</li>
<li>
<div class="ui-radio">
<input type="radio" value="Disagree" name="0" id="2">
</div>
</li>
<li>
<div class="ui-radio">
<input type="radio" value="Neutral" name="0" id="3">
</div>
</li>
<li>
<div class="ui-radio">
<input type="radio" value="Agree" name="0" id="4">
</div>
</li>
<li>
<div class="ui-radio">
<input type="radio" value="Strongly agree" name="0" id="5">
</div>
</li>
</ul>
</div>
</div>
</div>
<div class="row">
<div class="optionsContainer">
<div class="ratingContainer">
<ul class="0">
<li>
<div class="ui-radio">
<input type="radio" value="Strongly disagree" name="1" id="1">
</div>
</li>
<li>
<div class="ui-radio">
<input type="radio" value="Disagree" name="1" id="2">
</div>
</li>
<li>
<div class="ui-radio">
<input type="radio" value="Neutral" name="1" id="3">
</div>
</li>
<li>
<div class="ui-radio">
<input type="radio" value="Agree" name="1" id="4">
</div>
</li>
<li>
<div class="ui-radio">
<input type="radio" value="Strongly agree" name="1" id="5">
</div>
</li>
</ul>
</div>
</div>
</div>
&#13;
答案 1 :(得分:1)
看起来您已经知道如何计算已检查的元素。如果你把它放在第一个循环中,你可以标记一个变量false,如果有空的话。
var names = [];
var allChecked = true;
$('input[type="radio"]').each(function() {
// Creates an array with the names of all the different checkbox group.
names[$(this).attr('name')] = true;
if $(this).filter(':checked').length === 0 {
allChecked = false;
}
});
答案 2 :(得分:0)
https://jsfiddle.net/eu6L1f80/2/
<强>使用Javascript:强>
$('form').on('submit', function(e) {
e.preventDefault();
var checkboxes = {};
$(':checkbox').each(function() {
checkboxes[$(this).attr('name')] = true;
});
$.each(checkboxes, function(i, val) {
if($(':checkbox[name='+i+']').is(':checked')) delete checkboxes[i];
});
if (!Object.keys(checkboxes).length) {
alert('success!');
} else {
alert('error!');
}
});
<强> HTML:强>
<form>
<div>
Group:
<input type="checkbox" name="group1" value="" />
<input type="checkbox" name="group1" value="" />
<input type="checkbox" name="group1" value="" />
</div>
<div>
Group:
<input type="checkbox" name="group2" value="" />
<input type="checkbox" name="group2" value="" />
<input type="checkbox" name="group2" value="" />
</div>
<div>
Group:
<input type="checkbox" name="group3" value="" />
<input type="checkbox" name="group3" value="" />
<input type="checkbox" name="group3" value="" />
</div>
<button type="submit">Submit</button>
<form>