import pickle
def startover():
#Tells the user what number corresponds with what class.
print('1 = classA, 2 = classB, 3 = classC')
#accepts an input for what class the user would like to view.
Class=int(input('Choose the class you would like to view.'))
#If class a is selected, open class a.
if Class == int('1'):
ClassA=open('Class6A.txt','rb')
clsa=pickle.load(ClassA)
print(clsa)
#If class b is selected, open class b.
if Class == int('2'):
ClassB=open('Class6B.txt','rb')
clsb=pickle.load(ClassB)
print(clsb)
#If class c is selected, open class c.
if Class == int('3'):
ClassC=open('Class6C.txt','rb')
sorttype=int(input('How do you want to sort this data? 1=alphabetical 2=High to low by highest number 3=High to low by average number.'))
clsc=pickle.load(ClassC)
print(clsc)
file=('Class6A.txt','rb')
startover()
我希望能够按用户按字母顺序对选定的代码进行排序，以便他们可以使用代码输出的分数轻松找到名称。
Inside Class6a.txt
:€}q (X WHITE SAMq]q(KK KeX WILLIAMS GABRIELLEq]q(K
KKeX
NATHAN WILSONq]q(KK KeX SMITH ISABELLEq]q(KK KeX
CLARK BRANDONq ]q
(KKKeX PATEL SAPNAq]q(KKKeX
BROWN ADAMq
]q(KK
KeX JONES CHLOEq]q(KKKeX
DAVIS RYANq]q(K
KK eX MILLER NOELq]q(KKKeu.
在python中打开Class6A.txt： {＆＃39; WILLIAMS GABRIELLE＆＃39;：[10,6,2]，＆＃39; JONES CHLOE＆＃39;：[7,5,5]，＆＃39; MILLER NOEL＆＃39;：[1， 8,6]，＆＃39; CLARK BRANDON＆＃39;：[8,6,1]，＆＃39; NATHAN WILSON＆＃39;：[7,9,6]，＆＃39; SMITH ISABELLE＆＃39; ：[2,9,6]，＆＃39; WHITE SAM＆＃39;：[1,9,5]，＆＃39; BROWN ADAM＆＃39;：[8,10,6]，＆＃39; PATEL SAPNA＆＃39;：[7,8,7]，＆＃39; DAVIS RYAN＆＃39;：[10,6,9]}
答案 0 :(得分：3)
演示：
import pickle
d = {'WILLIAMS GABRIELLE': [10, 6, 2], 'JONES CHLOE': [7, 5, 5],\
'MILLER NOEL': [1, 8, 6], 'CLARK BRANDON': [8, 6, 1],\
'NATHAN WILSON': [7, 9, 6], 'SMITH ISABELLE': [2, 9, 6],\
'WHITE SAM': [1, 9, 5], 'BROWN ADAM': [8, 10, 6], 'PATEL SAPNA': [7, 8, 7],\
'DAVIS RYAN': [10, 6, 9]}
with open("Class6A.txt", "wb") as fp:
pickle.dump(d, fp)
import pickle
import collections
def getAverage(data):
""" Create Average of student data """
records = dict()
for i, j in data.iteritems():
records[i] = (j, float(sum(j))/len(j))
return records
def startover():
#. Tells the user what number corresponds with what class.
print('1 = classA, 2 = classB, 3 = classC')
#. accepts an input for what class the user would like to view.
while 1:
try:
class_no = int(raw_input('Choose the class you would like to view.'))
if class_no not in [1,2,3]:
print "Enter vlaid Class Number."
continue
break
except ValueError:
print "Enter valid Class Numner i.e.digit"
continue
#. If class a is selected, open class a.
if class_no==1:
file_name = 'Class6A.txt'
#If class b is selected, open class b.
elif class_no==2:
file_name = 'Class6B.txt'
#If class c is selected, open class c.
elif class_no==3:
file_name = 'Class6C.txt'
while 1:
try:
sorttype = int(raw_input('How do you want to sort this data? 1=alphabetical\
2=High to low by highest number 3=High to low by average number.'))
if sorttype not in [1,2,3]:
print "Enter vlaid option from the list.."
continue
break
except ValueError:
print "Enter valid option Number i.e. digit"
continue
# fp = open(file_name, 'rb')
# data = pickle.load(fp)
# fp.close()
with open(file_name, "rb") as fp:
data = pickle.load(fp)
#- Add Average value in data.
records = getAverage(data)
if sorttype==1:
student_names = records.keys()
student_names = sorted(student_names)
elif sorttype==3:
student_names = []
tmp = collections.defaultdict(list)
for i, j in records.iteritems():
tmp[j[1]].append(i)
tmp1 = tmp.keys()
tmp1 = sorted(tmp1)
tmp1.reverse()
for i in tmp1:
student_names.extend(tmp[i])
elif sorttype==2:
student_names = []
print "Try your self."
print "Result:"
print "Name\t Marks\t Average"
for i in student_names:
print "%s\t%s\t%s"%(i, records[i][0], records[i][1])
startover()
<强>输出：
1 = classA, 2 = classB, 3 = classC
Choose the class you would like to view.1
How do you want to sort this data? 1=alphabetical 2=High to low by highest number 3=High to low by average number.1
Result:
Name Marks Average
BROWN ADAM [8, 10, 6] 8.0
CLARK BRANDON [8, 6, 1] 5.0
DAVIS RYAN [10, 6, 9] 8.33333333333
JONES CHLOE [7, 5, 5] 5.66666666667
MILLER NOEL [1, 8, 6] 5.0
NATHAN WILSON [7, 9, 6] 7.33333333333
PATEL SAPNA [7, 8, 7] 7.33333333333
SMITH ISABELLE [2, 9, 6] 5.66666666667
WHITE SAM [1, 9, 5] 5.0
WILLIAMS GABRIELLE [10, 6, 2] 6.0
--------------------
1 = classA, 2 = classB, 3 = classC
Choose the class you would like to view.1
How do you want to sort this data? 1=alphabetical 2=High to low by highest number 3=High to low by average number.3
Result:
Name Marks Average
DAVIS RYAN [10, 6, 9] 8.33333333333
BROWN ADAM [8, 10, 6] 8.0
PATEL SAPNA [7, 8, 7] 7.33333333333
NATHAN WILSON [7, 9, 6] 7.33333333333
WILLIAMS GABRIELLE [10, 6, 2] 6.0
SMITH ISABELLE [2, 9, 6] 5.66666666667
JONES CHLOE [7, 5, 5] 5.66666666667
WHITE SAM [1, 9, 5] 5.0
MILLER NOEL [1, 8, 6] 5.0
CLARK BRANDON [8, 6, 1] 5.0
如果-elif的-ELSE
当我们想要在同一个变量上检查多个条件时使用if elif else。
<强>演示：
>>> a = 51
>>> if a<0:
... print "Number is negative."
... elif a==0:
... print "Number is Zero."
... else:
... print "Number is greater than 0"
...
Number is greater than 0
异常处理：
在try expet期间使用Value Error来捕获type casting例外情况。
演示：
>>> a = raw_input("Enter option:")
Enter option:f
>>> a
'f'
>>> int(a)
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
ValueError: invalid literal for int() with base 10: 'f'
>>> try:
... int(a)
... except ValueError:
... print "Enter digit only.."
...
Enter digit only..
注意：
对Python 2.x使用raw_input
使用Python 3.x的输入
答案 1 :(得分：1)
您的pickle文件中包含dict。您想要阅读dict.items()和内置sorted()函数的文档 - 这应该足以解决您的问题。
注意：我不会给你准确的（而且很简单）代码，因为它确实看起来像是家庭作业。