我有两个实体类Contact
和User
。
User
有ContactID
作为Contact
的外键。我可以显示User
与Contact
的关系。
现在我还需要Contact
与User
关系User
表中的相同外键(不在Contact
中)
public class Contact{
public int ContactID {get;set;}
// This relation doesn't work
// Need to Make this Work
public User ContactUser {get;set;}
}
public class User {
public string Id {get;set;}
public int? ContactID {get;set;}
// This Relation works
[ForeignKey("ContactID")]
public Contact Contact {get;set;}
}
所以我需要让ContactUser
关系适用于Contact
。我应该使用什么样的映射?
修改
正如我建议的那样:
modelBuilder.Entity<Contact>().HasRequired(c => c.ContactUser).WithOptional(pi => pi.Contact);
我从ForeignKey
移除了User
属性,导致Multiplicity...error
但我收到的错误如:Invalid column name 'User_Id'.
答案 0 :(得分:0)
您正在寻找的是
一到零或一映射
StackOverflow上有一个很棒的回音。
在您的案例中,显式是必需的:
modelBuilder需要WithOptional-Methode
.WithOptional(pi => pi.Contact);
ContactID
public class Contact
{
[Key]
public int ContactId { get; set; }
public string ContactName { get; set; }
public User ContactUser { get; set; }
}
public class User
{
[Key]
public int UserId { get; set; }
public string UserName { get; set; }
public Contact Contact { get; set; }
}
在DbContext-Class中:
public class CodeFirstContext : DbContext
{
public CodeFirstContext()
{
Database.SetInitializer(new DropCreateDatabaseIfModelChanges<CodeFirstContext>());
}
public DbSet<Contact> Contacts { get; set; }
public DbSet<User> Users { get; set; }
protected override void OnModelCreating(DbModelBuilder modelBuilder)
{
modelBuilder.Entity<User>()
.HasRequired(co => co.Contact)
.WithOptional(cu => cu.ContactUser);
base.OnModelCreating(modelBuilder);
}
}
在此案例中,现在说User的Contact属性是可选的,并且需要Contact的User属性。 我希望这是您项目的正确星座。
class Program
{
static void Main(string[] args)
{
using (var db = new CodeFirstContext())
{
Console.Write("Enter a name: ");
var name = Console.ReadLine();
var cont = new Contact { ContactName = name };
db.Contacts.Add(cont);
db.SaveChanges();
var usr = new User { UserName = "MyUsername", Contact = cont };
db.Users.Add(usr);
db.SaveChanges();
var query = from b in db.Contacts
orderby b.ContactName
select b;
Console.WriteLine("All contacts in the database:");
foreach (var item in query)
{
Console.WriteLine(item.ContactName);
}
Console.WriteLine("Press any key to exit...");
Console.ReadKey();
}
}
}
答案 1 :(得分:0)
试试这个:
public class Contact
{
[Key, DatabaseGenerated(DatabaseGeneratedOption.None)]
public int ContactId { get; set; }
public string ContactName { get; set; }
[ForeignKey("ContactId")]
public User ContactUser { get; set; }
}