Question

我试图制作一个破解密码游戏，但由于某些原因它无法正常工作请帮助

done = 0
guess = 0
import random
a=random.randrange(0,9)
str(a)
b=random.randrange(0,9)
str(b)
c=random.randrange(0,9)
str(c)
d=random.randrange(0,9)
str(d)

print a,b,c,d  #Its on so I can guess the correct number

while done == 0:

   ag=raw_input("Input a single digit between 9 and 0  :  ")
   bg=raw_input("Input a single digit between 9 and 0  :  ")
   cg=raw_input("Input a single digit between 9 and 0  :  ")
   dg=raw_input("Input a single digit between 9 and 0  :  ")
   print ag,bg,cg,dg
   if ag == a and bg == b and cg == c and dg == d:
      print "Well Done! You Got it correct in " ,guess, " times!" 
      done = 1
   else:
      print "Incorrect"
      if ag == a :
         print "You succsessfully guessed the first number!"
      if bg == b :
         print "You succsessfully guessed the second number!"
      if cg == c :
         print "You succsessfully guessed the third number!"
      if dg == d :
         print "You succsessfully guessed the forth number!"

我认为这应该有效，因为当我得到一些正确的数字时，它会打印出你得到的＆＃34; n＆＃34;数字是正确的，但总是出现这个：

 >> 5 8 3 3
 >> Input a single digit between 9 and 0  :  5
 >> Input a single digit between 9 and 0  :  8
 >> Input a single digit between 9 and 0  :  3
 >> Input a single digit between 9 and 0  :  3
 >> 5 8 3 3
 >> Incorrect

Answer 1

执行str(a)时，它不会将a转换为字符串。为此，请a = str(a)。

由于a当前是整数，后来将a与ag进行比较等等，检查失败。

您需要对当前代码中的b，c，d执行相同操作。

Answer 2

done = 0
guess = 0
import random
a=random.randrange(0,9)
b=random.randrange(0,9)
c=random.randrange(0,9)
d=random.randrange(0,9)
print a,b,c,d  #Its on so I can guess the correct number

while done == 0:

   ag=int(raw_input("Input a single digit between 9 and 0  :  "))
   bg=int(raw_input("Input a single digit between 9 and 0  :  "))
   cg=int(raw_input("Input a single digit between 9 and 0  :  "))
   dg=int(raw_input("Input a single digit between 9 and 0  :  "))
   print ag,bg,cg,dg
   if ag == a and bg == b and cg == c and dg == d:
      print "Well Done! You Got it correct in " ,guess, " times!" 
      done = 1
   else:
      print "Incorrect"
      if ag == a :
         print "You succsessfully guessed the first number!"
      if bg == b :
         print "You succsessfully guessed the second number!"
      if cg == c :
         print "You succsessfully guessed the third number!"
      if dg == d :
         print "You succsessfully guessed the forth number!"

现在我认为你有正确的想法如何解决这个问题。

为什么忽略多行？

2 个答案: