使用scanner类输入数组(错误:不兼容类型:扫描程序无法转换为String)

时间:2015-04-20 02:12:06

标签: java arrays java.util.scanner

我正在尝试使用扫描仪输入学生详细信息,但我一直收到此错误:

error: incompatible types: Scanner cannot be converted to String

我有4个扫描仪

static Scanner name = new Scanner(System.in);
static Scanner Date = new Scanner(System.in);
static Scanner address = new Scanner(System.in);
static Scanner gender = new Scanner(System.in);

我的代码如下

System.out.println("You have chosen to add a student. Please enter the following details");
System.out.println("Name: ");
String Name = name.nextLine();  
System.out.println("DOB: ");
String DOB = Date.nextLine();
System.out.println("Address: ");
String Address = address.nextLine();
System.out.println("Gender: ");
String Gender = gender.nextLine();

app.addStudent(name, DOB, address, gender);
System.out.println(Name + " has been added!" + "\n" + "Returning to menu....");

app.delay();

addStudent方法如下

public void addStudent (String name,String DOB,String address,String gender)
{
    for(int i = 0; i < enrolment.length; i++)
    {
        if (enrolment[i] == null)
        {
            this.enrolment[size] = new Student(name, DOB, address, gender);
            this.size++;

            if (gender == "Male")
            { 
                this.maleStudents++;
            }
            else { 
                this.femaleStudents++; 
            }
            break;
        }
    }
}

3 个答案:

答案 0 :(得分:5)

问题是您将Scanner个对象传递给addStudent方法,而不是从扫描仪获取的字符串:

app.addStudent(name, DOB, address, gender);

应该是

app.addStudent(Name, DOB, Address, Gender);

此外:

  • 一个Scanner对象就足够了。不需要四个。
  • Java代码约定规定变量名称为较低的驼峰式,即gender而不是Gender

将所有内容放在一起,您的代码应如下所示:

Scanner scanner = new Scanner(System.in);

System.out.println("You have chosen to add a student. Please enter the following details");

System.out.println("Name: ");
String name = scanner.nextLine();

System.out.println("DOB: ");
String dob = scanner.nextLine();

System.out.println("Address: ");
String address = scanner.nextLine();

System.out.println("Gender: ");
String gender = scanner.nextLine();

app.addStudent(name, dob, address, gender);

System.out.println(name + " has been added!" + "\n" + "Returning to menu....");

答案 1 :(得分:1)

您只需要一台扫描仪,而不是每台输入一台扫描仪。

在您的代码中,您将Name(字符串)与name(扫描仪)混淆。

这就是为什么有命名规则。

尝试更改为

 Scanner input = new Scanner (System.in);

 String name = input.nextLine ();
 String gender = input.nextLine (); 
 ...

然后

 app.addStudent (name, dob, address, gender);

还尝试阅读naming conventions

答案 2 :(得分:0)

名称,地址和性别是扫描仪,您的方法采用字符串

app.addStudent(Name, DOB, Address, Gender);

是使用您定义的String变量的方法