Question

我正在尝试使用rails 4，acts_as_list gem和jQuery来对（scrape）所拥有的表中的项目（页面）进行排序。我认为我的问题可能在于控制器方法，任何帮助都会非常感激。排序在前端工作得很好，trs上下移动，就像railscast显示的那样。但它没有更新位置，刷新之后又回到原来的状态。

这是我的控制器方法排序

def sort
  @scrape = Scrape.find(params[:scrape_id])
  @pages = @scrape.pages

  @pages.each_with_index do |id, index|
    Page.where(position: id).update_all({position: index+1})
  end
  render nothing: true
end

这是我的观点

= form_for @scrape do |f|
  %p    
    = f.label :url
    = f.text_field :website

  %table#pages
    %tbody{"data-update-url" => sort_scrape_pages_url(@scrape)}
      = f.fields_for :pages, @pages do |page_type|
        = content_tag_for :tr, page_type.object do
          %td=page_type.object.position     

          %td               
            = link_to page_type.object.url, scrape_page_path(@scrape, page_type.object.id)
          %td               
            = page_type.collection_select :page_type, ["Service Page", "Homepage","About Us", "Contact Us", "Informational", "Sitemap", "Privacy Policy", "Terms", "Blog"], :to_s, :humanize    
  = f.submit "Submit"

这是我的jQuery：

jQuery ->
  $('#pages tbody').sortable
  axis: 'y'
  update: ->
    $.post($(this).data('update-url'), $(this).sortable('serialize'))

这就是我的控制台所说的发生的事情，如果这对任何人都有帮助，我就不会这样做。

 Started POST "/scrapes/3/pages/sort" for 127.0.0.1 at 2015-04-19 18:28:56 -0700
 Processing by PagesController#sort as */*
 Parameters: {"page"=>["18", "17", "19", "20", "21", "22", "23", "24"], "scrape
 _pages_attributes_0"=>["id"], "scrape_pages_attributes_1"=>["id"], "scrape_pages
 _attributes_2"=>["id"], "scrape_pages_attributes_3"=>["id"], "scrape_pages_attri
 butes_4"=>["id"], "scrape_pages_attributes_5"=>["id"], "scrape_pages_attributes_
 6"=>["id"], "scrape_pages_attributes_7"=>["id"], "scrape_id"=>"3"}
 Scrape Load (1.0ms)  SELECT "scrapes".* FROM "scrapes" WHERE "scrapes"."id" =
 $1 LIMIT 1  [["id", "3"]]
 Page Load (1.0ms)  SELECT "pages".* FROM "pages" WHERE "pages"."scrape_id" = $
 1 ORDER BY position ASC  [["scrape_id", 3]]
   SQL (2.0ms)  UPDATE "pages" SET "position" = 1 WHERE "pages"."id" = 17
   SQL (1.0ms)  UPDATE "pages" SET "position" = 2 WHERE "pages"."id" = 18
   SQL (0.0ms)  UPDATE "pages" SET "position" = 3 WHERE "pages"."id" = 19
   SQL (0.0ms)  UPDATE "pages" SET "position" = 4 WHERE "pages"."id" = 20
   SQL (0.0ms)  UPDATE "pages" SET "position" = 5 WHERE "pages"."id" = 21
   SQL (0.0ms)  UPDATE "pages" SET "position" = 6 WHERE "pages"."id" = 22
   SQL (1.0ms)  UPDATE "pages" SET "position" = 7 WHERE "pages"."id" = 23
   SQL (0.0ms)  UPDATE "pages" SET "position" = 8 WHERE "pages"."id" = 24
 Rendered text template (0.0ms)
 Completed 200 OK in 15ms (Views: 0.0ms | ActiveRecord: 6.0ms)

Answer 1

您正在通过ID找到错误的位置，但您需要找到按ID记录

所以你的方法，你需要替换你的代码

@pages.each_with_index do |id, index|
  Page.where(id: id).update_all(position: index + 1)
end

Answer 2

错误发生在我的控制器中。我的工作排序方法如下。

def sort
  params[:page].each_with_index do |id, index|
    Page.where(id: id).update_all(position: index + 1)
  end
  render nothing: true  
end

Rails 4. jQuery，Acts_as_list，嵌套模型，更新控制器中的位置

2 个答案: