Question

我需要编写一个允许用户选择密码的程序。密码必须是一个不包含空格的单个字符串。

密码长度必须为6个字符，必须有一个小写字母，必须有一个大写字母，并且必须至少有一个数字。
如果密码失败，则显示有关哪个条件未满足的错误消息。具体说明哪一个为1号。然后让它们重新进入。
用户输入有效密码后，请验证其原始密码。如果条目不匹配，则让它们从头开始。如果有效，则匹配州密码。

示例输出：

> Enter your password: Boy1

Password needs to have 6 or more characters.

> Enter your password: women1

Password needs to contain at least one uppercase letter.

> Enter your password: boy

Password needs to have 6 or more characters.

Password needs to contain at least one uppercase letter.

Password needs to contain at least one digit.

> Enter your password: Mtndew1

Now re-enter your password for verification: Mtndew

Password does not match. Start over.

> Enter your password: Mtndew1

Now re-enter your password for verification: Mtndew1

You have now entered a valid password.

这是我到目前为止所做的，但不知道如何将所有这些放在一起并使输出功能如上所述我运行它。

#include <iostream>
#include <cctype>
#include <cstring>

using namespace std;

//Function Prototype
void testNum(char[],int);

int main()
{
    const int SIZE = 7; //Array Size
    char password[SIZE]; //To hold password
    int length;

    length = strlen(password);

    //Get the password.
    do{
        cout << "Enter your password: ";
        cin.getline(password,SIZE);
        length = strlen(password);
        cout<< "Please enter a password with at least 6 characters.\n";
        cin.getline(password,SIZE);
        length = strlen(password);
    } while (length < 6);

    //Call function.
    testNum(password,SIZE);

    return 0;
}

//Function Definition
void testNum(char pswd[],int size)
{

    int count;
    for (count = 0; count<size-1; count++)
    {
        if (!isupper(pswd[count]))
            cout << "The password does not contain an uppercase letter.\n";
        if (!islower(pswd[count]))
            cout << "The password does not contain a lowercase letter.\n";
        if (!isdigit(pswd[count]))
            cout << "The password does not contain a digit.\n";
    }

}

Answer 1

我经常修改你的代码

你使用const int作为数组大小，但它不能用于另一个函数所以我使用enum PWSIZE
我在main中循环。如果所有案例都通过，那么打破循环
并且密码数组太小。在lencheck条件中说超过6charset但数组大小为6.它会使缓冲区溢出。我提供你改变std :: string

首先你得到第一次密码和检查案例（如上面的其他地方）接下来是重新输入检查

看起来有点脏，但这只是概念......

#include <iostream>
#include <cctype>
#include <cstring>

using namespace std;

enum PWSIZE //Array Size
{
    PASSWORD_SIZE = 20
};

//Function Prototype
int testNum(char []);
int re_enter(char []);

int main()
{
    char password[PASSWORD_SIZE]; //To hold password
    int length;

    length = strlen(password);
    while(1)
    {
        //Get the password.
        do{
            cout<< "Please enter a password with at least 6 characters.\n";
            cout << "Enter your password: ";
            cin.getline(password, PASSWORD_SIZE);
            length = strlen(password);
        }while(length < 6);

        //Call function.
        if(testNum(password))
            continue;           //if return 1 pass below
        if(re_enter(password))
            continue;

        break;
    }
    return 0;
}

int testNum(char pswd[])
{
    int count;
    bool upper_flag = 0, lower_flag = 0, digit_flag = 0;
    for (count = 0; count<strlen(pswd); count++)    //don't need to Size use strlen
    {

        if (isupper(pswd[count]))
            upper_flag = 1;
        else if (islower(pswd[count]))
            lower_flag = 1;
        else if (isdigit(pswd[count]))
            digit_flag = 1;
    }
    if(!upper_flag)
    {
        cout << "The password does not contain an uppercase letter.\n";
    }

    if(!lower_flag)
    {
        cout << "The password does not contain a lowercase letter.\n";
    }
    if(!digit_flag)
    {
        cout << "The password does not contain a digit.\n";
    }
    if(upper_flag && lower_flag && digit_flag)
        return 0;   //if all pass
    else
        return 1;
}

int re_enter(char  passwd[])
{
    char compare_password[PASSWORD_SIZE] = {0,};
    cout << "Re Enter Your password" <<endl;
    cin.getline(compare_password, PASSWORD_SIZE);
    if(strcmp(passwd, compare_password))
    {
        cout << "Password Not Match" << endl;
        return 1;
    }
    return 0;
}

密码验证程序

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