Question

碰巧我正在使用Python进行编程，而我正准备编写一个小型的剪纸剪刀游戏。

不幸的是，当我尝试运行我的脚本时，我收到以下错误：

file rps.py, line 53 in game    
   compare (move,choice)     
  NameError: name 'move' is not defined"

到目前为止，这是我的代码：

from random import randint
possibilities = ['rock', 'paper', 'scissors']

def CPU(list):
    i =  randint(0, len(list)-1)
    move = list[i]
    #print (str(move))
    return move

def User():
    choice = str(input('Your choice? (Rock [r], Paper[p], Scissors[s])'))
    choice = choice.lower()

    if choice == 'rock' or choice == 'r':
        choice = 'rock'
    elif choice == 'scissors' or choice =='s':
        choice = 'scissors'
    elif choice == 'paper' or choice == 'p':
        choice = 'paper'

    #print ('Your choice: ' + str(choice))
    return choice


def compare(c, u):
    if c == u:
         print ('Your choice was: ' + str(u) + 'and I chose: ' + str(c))
         print ('That is what we call a tie. Nobody wins.')
    elif c == 'paper' and u == 'rock':
         print ('Your choice was: ' + str(u) + 'and I chose: ' + str(c))
         print ('This means that you, my friend, lose.')
    elif c == 'paper' and u == 'scissors':
         print ('Your choice was: ' + str(u) + 'and I chose: ' + str(c))
         print ('Congratulations, you win....this time.')
    elif cc == 'rock' and u == 'paper':
         print ('Your choice was: ' + str(u) + 'and I chose: ' + str(c))
         print ('Congratulations, you win....this time.')
    elif c == 'rock' and u == 'scissors':
         print ('Your choice was: ' + str(u) + 'and I chose: ' + str(c))
         print ('This means that you lose.')
    elif c == 'scissors' and u == 'paper':
         print ('Your choice was: ' + str(u) + 'and I chose: ' + str(c))
         print ('This means that you lose.')
    elif c == 'scissors' and u == 'rock':
         print ('Your choice was: ' + str(u) + 'and I chose: ' + str(c))
         print ('Congratulations, you win....this time.')

def game():
    CPU(possibilities)
    User()
    compare(move, choice)

game()

当我定义函数compare(c,u)并在括号中添加参数'c'和'u'时，我确信我做错了。我以为我确保通过使用之前的return语句来使用这些变量。

我对编程很新，因此缺乏经验，所以请善待！

Answer 1

问题是您只调用函数CPU和User，但您没有将它们分配给任何变量。因此，您需要在

中重新定义函数game

def game():
    move = CPU(possibilities)
    choice = User()
    compare(move, choice)

这样，在调用其他两个函数后，您将使用值compare的本地副本调用函数return。

您可以参考官方documentation

，详细了解功能和return声明

在另一个函数中调用函数，导致括号中的参数导致错误

1 个答案: