当我尝试编译下面的代码时,我收到一个错误:
src/main.cpp:51:48: error: no matching member function for call to 'child_value'
std::cout << "which has value" << eb.second.child_value(kv.second);
~~~~~~~~~~^~~~~~~~~~~
我不明白的是我能够在上面的循环中使用它。我只能假设它要我使用kv.second.child_value(kv.second);
代替。但是我希望它在for (auto& eb: mapb) {
返回的xml上运行此代码。
#include "pugi/pugixml.hpp"
#include <iostream>
#include <string>
#include <map>
int main()
{
const std::map<std::string, std::string> tagMap {
{"description", "content"}, {"url", "web_address"}
};
pugi::xml_document doca, docb;
std::map<std::string, pugi::xml_node> mapa, mapb;
if (!doca.load_file("a.xml") || !docb.load_file("b.xml")) {
std::cout << "Can't find input files";
return 1;
}
for (auto& node: doca.child("data").children("entry")) {
const char* id = node.child_value("id");
mapa[id] = node;
}
for (auto& node: docb.child("data").children("entry")) {
const char* idcs = node.child_value("id");
if (!mapa.erase(idcs)) {
mapb[idcs] = node;
}
}
// For removed
for (auto& ea: mapa) {
std::cout << "Removed:" << std::endl;
ea.second.print(std::cout);
}
// For added nodes
for (auto& eb: mapb) {
// Loop through tag map
for (auto& kv : tagMap) {
// Try to find the tag name named in second map value
// and associate it to the type of information in first map value
std::cout << "Found" << kv.first;
std::cout << "which has value" << eb.second.child_value(kv.second);
}
}
}
如果有人能解释我做错了什么,我真的很感激。
答案 0 :(得分:5)
根据找到的两个重载here
// Get child value of current node; that is, value of the first child node of type PCDATA/CDATA
const char_t* child_value() const;
// Get child value of child with specified name. Equivalent to child(name).child_value().
const char_t* child_value(const char_t* name) const;
您需要将指针传递给字符串(或字符串文字)。
std::cout << "which has value" << eb.second.child_value(kv.second.c_str());
^^^^^^^^^^^^^^^^^