的模板

Question

我知道Django有get_previous_by_FOO和get_next_by_FOO方法，但我不知道如何在我的模板和视图中使用它们。所以，请帮我把这两种方法用于我的项目。

我正在运行Django1.7和Python2.7，我的应用名称为blog 这是我的相应文件：

博客/ views.py

def view_post(request, slug):
    post = get_object_or_404(Post, slug=slug)
    return render_to_response('blog/blog_post.html',
            {
                'post':post,
            },
            context_instance=RequestContext(request))



class PublishedPostMixin(object):
    def get_queryset(self):
        return self.model.objects.live()


class PostDetailView(PublishedPostMixin,DetailView):
    model = Post

博客/ models.py

class Post(models.Model):
    created_at = models.DateTimeField(auto_now_add=True, editable=False)
    updated_at = models.DateTimeField(auto_now=True, editable=False)
    title = models.CharField(max_length=255)
    slug = models.SlugField(max_length=255,unique=True) 
    content = MarkdownField()
    published = models.BooleanField(default=True)
    author = models.ForeignKey(User, related_name="posts")
    tags = models.ManyToManyField(Tag)

    class Meta:
        ordering = ["-created_at", "title"]

    def __unicode__(self):
        return self.title

    def save(self, *args, ** kwargs):
        if not self.slug:
            self.slug = slugify(self.title) #title become the slug
        super(Post, self).save(*args,**kwargs)

    @models.permalink
    def get_absolute_url(self):
        return ("blog:detail",(),{'slug':self.slug
                            })

博客/ urls.py

urlpatterns = patterns('',
    url(r"^(?P<slug>[\w-]+)/$",view_post, name="detail"),
)

的模板

<p>
   {{ post.content|markdown }}
</p>
<ul class="pager">
   <li class="previous">
      <a href="{{post.get_previous_by_created_at}}">&larr; Previous Posts</a>
   </li>
   <li class="next">
      <a href="{{post.get_next_by_created_at}}">Next Posts &rarr;</a>
   </li>
</ul>

Answer 1

最后，我通过在模板中引入url标记解决了这个问题。这是我修改过的模板。

{% load url from future %}    
<ul class="pager">
        {% if post.get_next_by_created_at %}
            <li class="previous">
                 <a href="{% url 'blog:detail' post.get_next_by_created_at.slug %}">&larr; Previous Post</a>
            </li>
        {% endif %}
        {% if post.get_previous_by_created_at %}
            <li class="next">
                 <a href="{% url 'blog:detail' post.get_previous_by_created_at.slug %}">Next Post &rarr;</a>
            </li>
        {% endif %}
    </ul>

如何在我的Django博客中获取上一篇和下一篇文章？

的模板

1 个答案: