Question

我有一个像这样的JSON字符串：

[
{
"locationID" : "1",        
"name" : "Trdinova lokacija",
"address":{
    "address1": "Trdinova ulica 9",
    "address2": "",
    "zipCode":  "1000",
    "city":     "Ljubljana",
    "country":  "Slovenija"
},
"geoLocation":{
    "latitude": 46.05570,
    "longitude": 14.50705,
},
"workingTime" : "8:00 - 18:00",
"parkingPlaces" : 10,
"href": "/locations/{id}",
"numberOfCarsOnLocation" : 10
},
{
"locationID" : "2",        
"name" : "Dunajska lokacija",
"address":{
    "address1": "Dunajska cesta 140",
    "address2": "",
    "zipCode":  "1000",
    "city":     "Ljubljana",
    "country":  "Slovenija"
},
"geoLocation":{
    "latitude": 46.07980,
    "longitude": 14.51309,
},
"workingTime" : "8:00 - 18:00",
"parkingPlaces" : 10,
"href": "/locations/{id}",
"numberOfCarsOnLocation" : 10
}
]

这样的位置类：

public class Location {
    private String locationID;
    private String name;
    private String address1;
    private String address2;
    private String zipCode;
    private String city;
    private String country;
    private String workingTime;
    private String href;
    private String distance;

    private double latitude;
    private double longitude;

    private int parkingPlaces;
    private int numberOfCarsOnLocation;
}

我试图像这样解析它：

locationArrayList = gson.fromJson(responseString, new TypeToken<List<ACLocation>>(){}.getType());

我没有收到任何错误，但是当我尝试访问值（例如address1）时，它返回null。只有顶级值（如locationID，name ...）才有效。但是，如果我尝试访问较低级别的值（address1，纬度...），则返回null。

我猜我不能直接将较低级别的值读入变量，但是如何才能正确地完成这些？

谢谢！

Answer 1

您的address1，address2 ...字段位于JSON对象中，因此在Location类中，您必须具有address属性，如：

public class Location {
    private String locationID;
    private String name;
    private Address address
    ...
}

Address类看起来像：

public class Address {
    private String address1;
    private String address2;
    private String zipCode;
    private String city;
    private String country;
}

geoLocation字段的推理相同。

使用GSON解析JSON无法正常工作。变量是空的

1 个答案: