Question

这是我教授的任务，制作披萨菜单：每个馅料的比萨饼价格为10美元加额外费用：奶酪：2美元;番茄1美元，蘑菇3美元，辣椒1美元

使用提示选择五个配件中的三个配件

使用for循环，如果测试计算披萨的总价

使用警报报告您的浇头和数组

使用其他提醒报告您的帐单和价格

我不明白的是如何使用＆＃39; for循环＆＃39;计算用户通过提示输入的所有浇头的价格

这是我到目前为止的js代码：

var pizza = 10
var toppings = [];
var price = [];

var t1 = "cheese";
var p1 = 2;

var t2 = "tomato";
var p2 = 1;

var t3 = "mushrooms";
var p3 = 3;

var t4 = "peppers";
var p4 = 1;

toppings.push(t1);
toppings.push(t2);
toppings.push(t3);
toppings.push(t4);

price.push(p1);
price.push(p2);
price.push(p3);
price.push(p4);

var meow = [];
var m1 = prompt("Choose a desired topping: cheese, tomato, mushrooms, or peppers");
var m2 = prompt("Choose another desired topping: cheese, tomato, mushrooms, or peppers");
var m3 = prompt("Choose another desired topping: cheese, tomato, mushrooms, or peppers");

meow.push(m1);
meow.push(m2);
meow.push(m3);

var total = [];
var desired = [];

for (var i = 0; i < toppings.length; i++) {
   for (var i = 0; i < price.length; i++) {
       desired.push(toppings[i] + price[i]);
   }
}

total.push(desired + pizza);
alert(total);

Answer 1

您的解决方案几乎就在那里，因为您需要进行一些小的更改才能使代码正常工作：

而不是使用var total[]数组使用普通变量：var total
使用meow数组而不是toppings数组
（可选）您可以使用price或toppings数组作为内部阵列

＆＃13;

var pizza = 10
var toppings = [];
var price = [];

var t1 = "cheese";
var p1 = 2;

var t2 = "tomato";
var p2 = 1;

var t3 = "mushrooms";
var p3 = 3;

var t4 = "peppers";
var p4 = 1;

toppings.push(t1);
toppings.push(t2);
toppings.push(t3);
toppings.push(t4);

price.push(p1);
price.push(p2);
price.push(p3);
price.push(p4);

var meow = [];
var m1 = prompt("Choose a desired topping: cheese, tomato, mushrooms, or peppers");
var m2 = prompt("Choose another desired topping: cheese, tomato, mushrooms, or peppers");
var m3 = prompt("Choose another desired topping: cheese, tomato, mushrooms, or peppers");

meow.push(m1);
meow.push(m2);
meow.push(m3);

var total = 0;
var desired = [];

for (var i = 0; i < meow.length; i++) {
    for (var j = 0; j < toppings.length; j++) {
        if (meow[i] == toppings[j]) 
            total = total + price[j];
    }
}

//total.push(desired + pizza);
alert("total " + total);

＆＃13;

请注意我认为为内部和外部for循环设置不同的变量是一个好习惯：j和i

Javascript：提示用户订购披萨配料，为配料分配价格并提醒总数？

1 个答案: