Question

我想使用Swift用英文字母替换一些字符。替换代码：

let turkish = ["ı", "ğ", "ü", "ş", "ö", "ç"]
let english = ["i", "g", "u", "s", "o", "c"]

var city = "Ağri"
var result = ""

for i in 0..<turkish.count {
    var target = turkish[i]
    var destination = english[i]

    result = city.stringByReplacingOccurrencesOfString(target, withString: destination, options: NSStringCompareOptions.CaseInsensitiveSearch | NSStringCompareOptions.LiteralSearch, range: nil)
}

它不会将“ğ”替换为“g”。奇怪的是，如果我直接输入它：

result = city.stringByReplacingOccurrencesOfString("ğ", withString: "g", options: NSStringCompareOptions.CaseInsensitiveSearch | NSStringCompareOptions.LiteralSearch, range: nil)

它完美无缺。

为什么不是，当我第一次将值赋给String变量时？

Answer 1

看起来你正试图删除各种口音和变音符号。您可以这样做的一种方法是使用CFStringTransform。

在Swift中它看起来像这样：

let original = "šÜįéïöç"
var mutableString = NSMutableString(string: original) as CFMutableStringRef
CFStringTransform(mutableString, nil, kCFStringTransformStripCombiningMarks, Boolean(0))

let normalized = (mutableString as NSMutableString).copy() as! NSString
// = sUieioc

修改

与pointed out by Martin R in the comments一样。没有Core Foundation，您也可以这样做：

let original = "šÜįéïöç"
let normalized = original.stringByFoldingWithOptions(.DiacriticInsensitiveSearch, locale: NSLocale.currentLocale())
// = sUieioc

Answer 2

发生这种情况是因为您替换了城市的出现次数，但是将新值分配给结果。这样只会在结果中替换最后一个字符。只需删除结果变量并更改此行：

result = city.stringByReplacingOccurrencesOfString(target, withString: destination, options: NSStringCompareOptions.CaseInsensitiveSearch | NSStringCompareOptions.LiteralSearch, range: nil)

到此：

city = city.stringByReplacingOccurrencesOfString(target, withString: destination, options: NSStringCompareOptions.CaseInsensitiveSearch | NSStringCompareOptions.LiteralSearch, range: nil)

Swift字符串替换发生

2 个答案:

修改