Question

我正在尝试使用XDOToool将一个简单的无限点击脚本与另一段脚本集成以检测键盘输入;按下某个键时结束正在运行的点击脚本，但不确定如何匹配它们。

此脚本无限次地重复点击屏幕光标点XXX，YYY由XDOTool确定

 #!/bin/bash
 while true [ 1 ]; do
 xdotool mousemove XXX YYY click 1 &
 sleep 1.5
 done

接下来我想使用类似的东西：

#!/bin/bash
if [ -t 0 ]; then stty -echo -icanon -icrnl time 0 min 0; fi
count=0
keypress=''
while [ "x$keypress" = "x" ]; do
let count+=1
echo -ne $count'\r'
keypress="`cat -v`"
done
if [ -t 0 ]; then stty sane; fi
echo "You pressed '$keypress' after $count loop iterations"
echo "Thanks for using this script."
exit 0

我不明白我是怎么做的：

 xdotool mousemove XXX YYY click 1 &
 sleep 1.5

如果把它放在上面的剧本中，BASH的混乱和MAN BASH并没有帮助，所以任何可以提供帮助的人都会受到赞赏。致谢

Answer 1

改进（和评论）的脚本：

#!/bin/bash

x_pos="0"   # Position of the mouse pointer in X.
y_pos="0"   # Position of the mouse pointer in Y.
delay="1.5" # Delay between clicks.

# Exit if not runs from a terminal.
test -t 0 || exit 1

# When killed, run stty sane.
trap 'stty sane; exit' SIGINT SIGKILL SIGTERM

# When exits, kill this script and it's child processes (the loop).
trap 'kill 0' EXIT

# Do not show ^Key when press Ctrl+Key.
stty -echo -icanon -icrnl time 0 min 0

# While the pears become pears...
while true; do
    xdotool mousemove "$x_pos" "$y_pos" click 1 &
    sleep "$delay"
done & # Note the &: We are running the loop in the background to let read to act.

# Pause until reads a character.
read -n 1

# Exit.
exit 0

BASH XDOTool鼠标单击，重复和停止

1 个答案: