我无法找到更好的方法。我将学生对象的所有属性映射到2D数组。所以我的电视有部分。
我也不能使用静态表视图,如果是这样,这个问题就不存在了。
所以我在TVC的代码
let currentUser = PFUser.currentUser()! as! MyUser
var membershipSection:[[String:String]]!
var detailsSection:[[String:String]]!
var emergancySection:[[String:String]]!
var medicalSection:[[String:String]]!
var titlesForSection = ["MEMBERSHIP", "DETAILS", "EMERGANCY CONTACT", "MEDICAL HISTORY"]
var combo = [[[String:String]]]() // Data Source for TableView
//从ViewDidLoad
调用以下内容func loadDisplayDataSource() {
combo.removeAll(keepCapacity: true)
var idString = "Awaiting ID Generation"
if student.objectId != nil {
idString = student.objectId!
}
membershipSection = [["Sessions":student.sessionsRemaining], ["Details":""], ["ID":idString]]
detailsSection = [["First Name":student.firstName], ["Last Name":student.lastName], ["DOB":""], ["Address":""], ["Phone":""], ["Email":student.email], ["Occupation":""]]
emergancySection = [["Name":""], ["Phone":""]]
medicalSection = [["Recent Surgery":""], ["Hypertension":""], ["Diabetes":""], ["Caradic":""], ["Epilesy":""], ["Syncope":""], ["Medications":""], ["Medical Details":""], ["Other Injuries":""]]
combo.append(membershipSection)
combo.append(detailsSection)
combo.append(emergancySection)
combo.append(medicalSection)
self.tableView.beginUpdates()
var range = NSMakeRange(0, self.numberOfSectionsInTableView(self.tableView))
var sections = NSIndexSet(indexesInRange: range)
self.tableView.deleteSections(sections, withRowAnimation: UITableViewRowAnimation.None)
self.tableView.insertSections(sections, withRowAnimation: UITableViewRowAnimation.Fade)
self.tableView.endUpdates()
}
有没有更好的方法将对象的数据映射到各个部分?我这样做的方式有效,但有点令人困惑。如果我可以使用静态视图,这将更容易,但我不能在普通VC中使用电视放映,你不能在这些中使用静态电视。哪个很烦人!有更清洁的方式吗?
我可以使其更加SWIFTY - 创建我的组合数据源的更好方法。
感谢您的任何建议。
我的最终结果 - 工作看起来像这样 - 带有部分的TVC。
答案 0 :(得分:1)
我不完全确定你在问什么。什么是'组合'用于?
如果您想以更干净的方式打包数据,Swift中的结构对此非常有用。类似的东西:
struct EmergencySection{
var name: String!
var phone: String!
}
//then to instantiate in loadDisplayDataSource
var emergencySection = EmergencySection(name: "", phone: "")
combo.append(emergencySection)
答案 1 :(得分:0)
以下是我的表现,更清洁
private struct Details {
static let title = "DETAILS"
static let firstName = (key:"First Name", index:0)
static let lastName = (key:"Last Name", index:1)
static let dob = (key:"DOB", index:2)
static let address = (key:"Address", index:3)
static let phone = (key:"Phone", index:4)
static let email = (key:"Email", index:5)
static let occupation = (key:"Occupation", index:6)
static func splitIntoDictionaries(student: Student) -> [[String:String]] {
return [
[firstName.key:student.firstName], // 0
[lastName.key:student.lastName], // 1
[dob.key:""],
[address.key:""],
[phone.key:""],
[email.key:student.email],
[occupation.key:""]
]
}
}
答案 2 :(得分:0)
尝试使用Wikipedia has an excellent in depth explanation.,这对于此类任务非常棒。好吧,它完全是Objective-C,但至少你可以快速看一下它。
答案 3 :(得分:0)
这个怎么样?
import UIKit
class
ViewController: UITableViewController {
var combo = [ [ String: AnyObject? ] ]()
let titlesForSection = ["MEMBERSHIP", "DETAILS", "EMERGANCY CONTACT", "MEDICAL HISTORY"]
override func
viewDidLoad() {
super.viewDidLoad()
// Something about studen data
combo = [
[ "Sessions":"student.sessionsRemaining", "Details":"", "ID":"idString" ]
, [ "First Name":"student.firstName", "Last Name":"student.lastName", "DOB":"", "Address":"", "Phone":"", "Email":"student.email", "Occupation":"" ]
, [ "Name":"", "Phone":"" ]
, [ "Recent Surgery":"", "Hypertension":"", "Diabetes":"", "Caradic":"", "Epilesy":"", "Syncope":"", "Medications":"", "Medical Details":"", "Other Injuries":"" ]
]
}
override func
numberOfSectionsInTableView(tableView: UITableView ) -> Int {
return combo.count
}
override func
tableView(tableView: UITableView, numberOfRowsInSection section: Int ) -> Int {
return combo[ section ].count
}
override func
tableView(tableView: UITableView, titleForHeaderInSection section: Int) -> String? {
return titlesForSection[ section ]
}
override func tableView( tableView: UITableView, cellForRowAtIndexPath indexPath: NSIndexPath ) -> UITableViewCell {
let v = tableView.dequeueReusableCellWithIdentifier( "SomeIdentifier" ) as! UITableViewCell
let w = combo[ indexPath.section ]
let wKey = Array( w.keys )[ indexPath.row ]
v.textLabel!.text = wKey
v.detailTextLabel!.text = w[ wKey ] as? String
return v
}
}
答案 4 :(得分:0)
通过将UITableViewController添加为普通的UIViewController,可以将其添加为子视图控制器。
parentVC.addChildViewController(childVC)
childVC.view.frame = parentVC.view.bounds
parentVC.view.addSubview(childVC.view)
childVC.didMoveToParentViewController(parentVC)