Question

我试图以这种方式绘制来自两个不同来源的在线数据：

在每次迭代中：

1]第一个来源：将输入数据添加到图表中。

2]第二个来源：删除以前的数据并仅保留图中的传入数据。

这是我的代码：

import plotly.plotly as py  
import plotly.tools as tls   
from plotly.graph_objs import *

import numpy as np
from sklearn.cluster import MeanShift, estimate_bandwidth
from sklearn.datasets.samples_generator import make_blobs
import time

py.sign_in('wajdi', 'key')

trace1 = Scatter(
    x=[],
    y=[],
    mode='markers',
    marker=Marker(
        color=[],
        opacity=1,
        line=Line(width=0.0),
        size=[],symbol='circle'),
    stream=Stream(token='troi4k35qp'),
)

trace2 = Scatter(
    x=[],
    y=[],
    mode='markers',
    marker=Marker(color=[]),
    stream=Stream(token='8lsvl6a79e')
)
data = Data([trace1,trace2])

layout = Layout(title='Time Series')

fig = Figure(data=data, layout=layout)

unique_url = py.plot(fig, filename='s7_first-stream')

s = py.Stream('8lsvl6a79e')
z = py.Stream('troi4k35qp')

s.open()
z.open()
print "waiting for brower..."
time.sleep(6)

centers = [[15, 15],[5, 5]]

for i in range(1000):
    X, _ = make_blobs(n_samples=2, centers=centers, cluster_std=1.0,center_box=(-1, 1))
    print i
    s.write(dict(x=X[0,0], y=X[0,1],marker=Marker(color='blue')))
    z.write(dict(x=X[1,0], y=X[1,1],marker=Marker(color='green',size=15))) 
    time.sleep(0.9)

    # I WANT TO REMOVE DATA WRITED IN Z STREAM HERE

s.close()
z.close()
print "finish"

Answer 1

您可以通过发送空数组来删除（或清除您喜欢的）数据。在您的情况下，只需添加

z.write(x=[], y=[])

有关完整示例，请参阅此ipython notebook：

python - plotly：从图中删除绘制的数据

1 个答案: