Question

我正在尝试使用我的VBA excel进行一些素数分解，并且我达到了long数据类型的限制 -

运行时错误6溢出

有没有办法解决这个问题，仍然留在VBA内？我知道显而易见的是使用另一种更合适的编程语言。

Lance's solution到目前为止工作，我现在可以将大数字输入变量。但是，当我尝试应用MOD函数 - 例如bignumber MOD 2时，它仍会失败并显示错误消息

运行时错误6溢出

Answer 1

您可以使用十进制数据类型。谷歌快速提示：http://www.ozgrid.com/VBA/convert-to-decimal.htm

Answer 2

这是我的Decimals.cls（VB6）：

VERSION 1.0 CLASS
BEGIN
  MultiUse = -1  'True
  Persistable = 0  'NotPersistable
  DataBindingBehavior = 0  'vbNone
  DataSourceBehavior  = 0  'vbNone
  MTSTransactionMode  = 0  'NotAnMTSObject
END
Attribute VB_Name = "Decimals"
Attribute VB_GlobalNameSpace = False
Attribute VB_Creatable = True
Attribute VB_PredeclaredId = False
Attribute VB_Exposed = True
Attribute VB_Ext_KEY = "SavedWithClassBuilder6" ,"Yes"
Attribute VB_Ext_KEY = "Top_Level" ,"Yes"
Option Explicit

'local variable(s) to hold property value(s)
Private mvarDec As Variant 'local copy

Public Property Let Dec(ByVal vData As Variant)
'used when assigning a value to the property, on the left side of an assignment.
'Syntax: X.Dec = 5
    mvarDec = CDec(vData)
End Property

Public Property Get Dec() As Variant
Attribute Dec.VB_UserMemId = 0
'used when retrieving value of a property, on the right side of an assignment.
'Syntax: Debug.Print X.Dec
    Dec = CDec(mvarDec)
End Property

这是一个测试程序。该类已经设置好，因此您不必在get和let上使用.Dec（）。

Dim dec1 As New Std.Decimals
Dim dec2 As New Std.Decimals
Dim dec3 As New Std.Decimals
Dim modulus As New Std.Decimals

Sub main()
    dec1 = "1000.000000001"
    dec2 = "1000.00000000000001"
    dec3 = dec1 + dec2
    Debug.Print dec1
    Debug.Print dec2
    Debug.Print dec3
    Debug.Print dec3 * dec3
    Debug.Print dec3 / 10
    Debug.Print dec3 / 100
    Debug.Print Sqr(dec3)
    modulus = dec1 - Int(dec1 / dec2) * dec2
    Debug.Print modulus
End Sub

和样本运行

 1000.000000001 
 1000.00000000000001 
 2000.00000000100001 
 4000000.000004000040000001 
 200.000000000100001 
 20.0000000000100001 
 44.721359550007 
 0.00000000099999 
 1000.000000001 
 1000.00000000000001 
 2000.00000000100001 
 4000000.000004000040000001 
 200.000000000100001 
 20.0000000000100001 
 44.721359550007 
 0.00000000099999

Answer 3

这是我的“大倍增”例程，用于乘以任意大数（例如100个字符长）。它的工作原理是将输入数字（字符串）拆分成7位数的块（因为它可以交叉乘以它们并将结果存储为双打）。

例如bigmultiply（“1934567803945969696433”，“4483838382211678”）= 8674289372323895422678848864807544574

Function BigMultiply(ByVal s1 As String, ByVal s2 As String) As String

Dim x As Long
x = 7

Dim n1 As Long, n2 As Long, n As Long
n1 = Int(Len(s1) / x + 0.999999)
n2 = Int(Len(s2) / x + 0.999999)
n = n1 + n2

Dim i As Long, j As Long
ReDim za1(n1) As Double
i = Len(s1) Mod x
If i = 0 Then i = x
za1(1) = Left(s1, i)
i = i + 1
For j = 2 To n1
 za1(j) = Mid(s1, i, x)
 i = i + x
Next j

ReDim za2(n2) As Double
i = Len(s2) Mod x
If i = 0 Then i = x
za2(1) = Left(s2, i)
i = i + 1
For j = 2 To n2
 za2(j) = Mid(s2, i, x)
 i = i + x
Next j

ReDim z(n) As Double
Dim u1 As Long, u2 As Long
Dim e As String
e = String(x, "0")

For u1 = 1 To n1
 i = u1
 For u2 = 1 To n2
   i = i + 1
   z(i) = z(i) + za1(u1) * za2(u2)
 Next u2
Next u1

Dim s As String, y As Double, w As Double, m As Long
m = n * x
s = String(m, "0")
y = 10 ^ x
For i = n To 1 Step -1
 w = Int(z(i) / y)
 Mid(s, i * x - x + 1, x) = Format(z(i) - w * y, e)
 z(i - 1) = z(i - 1) + w
Next i
'truncate leading zeros
For i = 1 To m
 If Mid$(s, i, 1) <> "0" Then Exit For
Next i
If i > m Then
 BigMultiply = ""
Else
 BigMultiply = Mid$(s, i)
End If

End Function

Answer 4

MOD尝试将DECIMAL类型转换为LONG，然后再对其进行操作。您可能需要为DECIMAL类型编写自己的MOD函数。你可以试试这个：

r = A - Int(A / B) * B

其中A＆amp; B是VARIANT变量的DECIMAL子类型，r也可能必须大（根据您的需要），尽管我只测试了很长时间。

长数据类型溢出

4 个答案: