Question

我需要发送一个PHP file_get_contents函数的文件。我使用下面的代码而且我没有得到......

$image['tmp_name']  = "/tmp/unnamed.png";
$image['file_image']    = base64_encode(file_get_contents("/tmp/unnamed.png"));
$image['name']      = "unnamed.png";
$image['file_name'] = "unnamed.png";
$image['type']      = "image/png";
$image['submit'] = "UPLOAD"; 

$url = 'http://localhost/api/upload_image';

$postdata = http_build_query(
    array(
        'file_name' => 'form variable1',
        'file_image' => file_get_contents($image['tmp_name'])
    )
);

$opts = array('http' =>
    array(
        'method'  => 'POST',
        'header' => 'Content-Type: multipart/form-data',
        'content' => $postdata
    )
);

$context  = stream_context_create($opts); 

var_export(file_get_contents($url, false, $context));

在我的python服务器上，我有以下代码：

class UploadImage(webapp.RequestHandler):
    def post(self):
        img         = Images()
        img.image   = self.request.get('file_image')
        img.name    = self.request.get('file_name') or "no name"
        img.put()

        self.response.headers.add_header('content-type', 'application/json', charset='utf-8')   
        self.response.out.write('{"status": "OK", "image": "'+img.key.urlsafe()+'"}')

我的图片是Google NDB模型，带有＆＃34; ndb.BlobProperty（）＆＃34;字段。

编辑： 有了这个CURL工作，但我不能在生产服务器中使用....

    $ch = curl_init(); 
    curl_setopt($ch, CURLOPT_URL, $url ); 
    curl_setopt($ch, CURLOPT_RETURNTRANSFER,1); 
    curl_setopt($ch, CURLOPT_POST, 1 ); 
    curl_setopt($ch, CURLOPT_POSTFIELDS, http_build_query($image) ); 

    $exec = curl_exec($ch);
    $info = curl_getinfo($ch);
    curl_close($ch);

    var_export($exec);

解决：

    $image['file_image'] = base64_encode(file_get_contents($image['tmp_name']));
    $image['file_name']  = "unnamed.png";

    $postdata = http_build_query($image);

    $opts = array('http' =>
        array(
            'method'  => 'POST',
            'content' => $postdata
        )
    );

    $context  = stream_context_create($opts);

    $result = file_get_contents($url, false, $data);
    $info   = $this->parse_http_response_header($http_response_header);

    var_export($result);

Answer 1

您应该将'标题'更改为'Content-Type：application / x-www-form-urlencoded'，您不需要求助于curl。有关示例，请参阅How to post data in PHP using file_get_contents?。

带有file_get_contents的PHP Post文件

1 个答案: