我有以下实体。 联系。人。组织。和Telefoon(英文电话)。
人员和组织都是联系人。他们继承自联系。
联系人可以有一个或多个语音。所以来自Telefoon的名单。
组织也有类型人员的联系人。
问题是如果我持久化Person对象和组织对象, 每个对象都有2个数字,对于某些对象,只有1个phoneNumber在数据库中存在?那怎么样?
我知道这与我的注释和我的课程配置有关。
班主任
@Entity
@Table(name= "Contact")
@Inheritance(strategy = InheritanceType.JOINED)
@XmlRootElement
public class Contact implements Serializable {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
private long id;
private String naam;
@Embedded
private Adres adres;
public Contact() {}
@OneToMany(mappedBy="contact", orphanRemoval=true,cascade = CascadeType.ALL)
@XmlElement
private List<Telefoon> telefoons=new ArrayList<>();
班级人员
@Entity
@Table(name="Persoon")
@Inheritance(strategy= InheritanceType.JOINED)
public class Persoon extends Contact implements Serializable{
@Convert(converter=LocalDatePersistenceConverter.class)
private LocalDate geboorteDatum;
protected Persoon() {}
@OneToMany(mappedBy="contactPersoon",orphanRemoval=true,cascade = CascadeType.ALL)
private List<Organisatie> Organisaties;
班级组织:
@Entity
@Inheritance(strategy = InheritanceType.JOINED)
public class Organisatie extends Contact implements Serializable{
protected Organisatie() {}
@JoinColumn(name = "persoonid")
@ManyToOne(cascade=CascadeType.ALL)
private Persoon contactPersoon;
班级电话(英语电话)
@Entity
@Table(name = "Telefoon")
public class Telefoon implements Serializable {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
private long id;
@Column(name = "nummer")
private String nummer;
@Column(name = "naam")
private String naam;
@JoinColumn(name = "contactid")
@ManyToOne
private Contact contact;
我以这种方式坚持我的对象:
persoon1.addTelefoon(new Telefoon("Huis","092243851"));
persoon1.addTelefoon(new Telefoon("Mobiel","0478451226"));
persoon2.addTelefoon(new Telefoon("Huis","095547812"));
persoon2.addTelefoon(new Telefoon("Mobiel","0425154578"));
persoon3.addTelefoon(new Telefoon("Huis","097784152"));
persoon3.addTelefoon(new Telefoon("Mobiel","0478221144"));
persoon4.addTelefoon(new Telefoon("Huis","095862314"));
persoon4.addTelefoon(new Telefoon("Mobiel","0423887799"));
persoon5.addTelefoon(new Telefoon("Huis","097841526"));
persoon5.addTelefoon(new Telefoon("Mobiel","0478220033"));
contactpersoon1.addTelefoon(new Telefoon("Huis","092261236"));
contactpersoon1.addTelefoon(new Telefoon("Mobiel","0499150327"));
contactpersoon2.addTelefoon(new Telefoon("Huis","097842615"));
contactpersoon2.addTelefoon(new Telefoon("Mobiel","0499369101"));
contactpersoon3.addTelefoon(new Telefoon("Huis","091142563"));
contactpersoon3.addTelefoon(new Telefoon("Mobiel","0452119987"));
organisatie1.addTelefoon(new Telefoon("Huis","094578956"));
organisatie1.addTelefoon(new Telefoon("Mobiel","0488125200"));
organisatie2.addTelefoon(new Telefoon("Huis","091247653"));
organisatie2.addTelefoon(new Telefoon("Mobiel","0487930287"));
organisatie3.addTelefoon(new Telefoon("Huis","09784561346"));
organisatie3.addTelefoon(new Telefoon("Mobiel","0476112233"));
em.getTransaction().begin();
em.persist(persoon1);
em.persist(persoon2);
em.persist(persoon3);
em.persist(persoon4);
em.persist(persoon5);
em.persist(organisatie1);
em.persist(organisatie2);
em.persist(organisatie3);
em.merge(contactpersoon1);
em.merge(contactpersoon2);
em.merge(contactpersoon3);
em.getTransaction().commit();
但数据库不会显示所有家庭和手机号码! 有些人被遗漏了!
有什么想法吗?
感谢名单
答案 0 :(得分:0)
我找到了答案。 Glassfish在数据库中保存日期时遇到问题。
类Person的date属性被转换为我编写自己的类。只是编辑数据库中日期的标记。
似乎玻璃鱼无法处理。 我还使用Organisatie(组织)列表删除了oneToMany。
这样:
YearMonth ym = YearMonth.of(2000, 2);
System.out.println(ym.lengthOfMonth()); //29 as expected
现在是这样的:
@Entity
@Table(name="Persoon")
@Inheritance(strategy= InheritanceType.JOINED)
public class Persoon extends Contact implements Serializable{
@Convert(converter=LocalDatePersistenceConverter.class)
private LocalDate geboorteDatum;
protected Persoon() {}
@OneToMany(mappedBy="contactPersoon",orphanRemoval=true,cascade = CascadeType.ALL)
private List<Organisatie> Organisaties;
现在一切正常! 感谢名单