我有一个tabBarController
和两个UINavigationControllers
UITableViews
附加到tabBarController
。我已经将tabBarController
子类化,因此我可以通过引用在两个表之间传递一组自定义对象。但是,当我去填充数组时,tableView
出口打开到nil并且我收到错误“致命错误:在展开Optional值时意外地发现了nil”。不知道为什么会这样。以下是代码:
tabBarController
protocol CustomTabBarDelegate {
var placeDataArray : Array <placeData> {get set}
}
class placeData: Equatable {
var description : String
var selected : Bool
init (description : String, selected : Bool) {
self.description = description
self.selected = selected
}
}
class PlacesTabBarController: UITabBarController {
var placeDataArray = Array<placeData>()
override func viewDidLoad() {
super.viewDidLoad()
placeDataArray = [placeData(description: "Afghanistan", selected: false), placeData(description: "Albania", selected: false)]
var table1 = AllPlacesViewController()
var table2 = AttendingPlacesTableViewController()
table1.delegate = self
table2.delegate = self
var navController1 = UINavigationController(rootViewController: table1)
var navController2 = UINavigationController(rootViewController: table2)
self.viewControllers = [navController1, navController2]
}
}
tableViewControllers
var delegate:PlacesTabBarController!
然后,例如,我可以通过调用
来访问该数组delegate.placeDataArray.count
当我用
填充表格时@IBOutlet weak var allPlacesTableView: UITableView!
并使用
var cell = self.allPlacesTableView.dequeueReusableCellWithIdentifier("Cell") as UITableViewCell
抛出上述错误。不确定allPlacesTableView
为什么要解包为
答案 0 :(得分:6)
当您像这样创建VC时,
var table1 = AllPlacesViewController()
它们与故事板没有关联,因此没有实现这些出口。请改用self.storyboard的instantiateViewControllerWithIdentifier
方法:
var table1 : AllPlacesViewController = UIStoryboard(name: "Main", bundle: nil).instantiateViewControllerWithIdentifier("AllPlaces") as AllPlacesViewController
答案 1 :(得分:0)
可能是您没有正确实例化ViewController。确保如果要从storybaord实例化VC,则必须这样做:
let storyboard = UIStoryboard(name: "YourStoryboardName", bundle: nil)
let someVC = storyboard.instantiateViewController(withIdentifier: "SomeViewController") as? SomeViewController