Question

如何在用户在searchView上搜索的指定行上放置onclicklistner。香港专业教育学院一直试图弄清楚如何，但当我这样做时，它总是显示第一行的吐司或Uri链接。任何人都可以帮助我吗？

例如，当我搜索ABC时，我想点击它以查看吐司或Uri链接，当我点击它时。

Employee.java

public class Employee {

private String name;
private int age;

public  Employee(String name,int age){
    this.name = name;
    this.age = age;
}

public String getName(){
    return name;
}

public int getAge(){
    return age;
}}

EmployeeAdapter.java

public class EmployeeAdapter extends BaseAdapter implements Filterable {

public Context context;
public ArrayList<Employee> employeeArrayList;
public ArrayList<Employee> orig;

public EmployeeAdapter(Context context, ArrayList<Employee> employeeArrayList) {
    super();
    this.context = context;
    this.employeeArrayList = employeeArrayList;
}


public class EmployeeHolder
{
    TextView name;
    TextView age;
}

public Filter getFilter() {
    return new Filter() {

        @Override
        protected FilterResults performFiltering(CharSequence constraint) {
            final FilterResults oReturn = new FilterResults();
            final ArrayList<Employee> results = new ArrayList<Employee>();
            if (orig == null)
                orig = employeeArrayList;
            if (constraint != null) {
                if (orig != null && orig.size() > 0) {
                    for (final Employee g : orig) {
                        if (g.getName().toLowerCase()
                                .contains(constraint.toString()))
                            results.add(g);
                    }
                }
                oReturn.values = results;
            }
            return oReturn;
        }

        @SuppressWarnings("unchecked")
        @Override
        protected void publishResults(CharSequence constraint,
                                      FilterResults results) {
            employeeArrayList = (ArrayList<Employee>) results.values;
            notifyDataSetChanged();
        }
    };
}

public void notifyDataSetChanged() {
    super.notifyDataSetChanged();
}


@Override
public int getCount() {
    return employeeArrayList.size();
}

@Override
public Object getItem(int position) {
    return employeeArrayList.get(position);
}

@Override
public long getItemId(int position) {
    return position;
}

@Override
public View getView(int position, View convertView, ViewGroup parent) {
    EmployeeHolder holder;
    if(convertView==null)
    {
        convertView=LayoutInflater.from(context).inflate(R.layout.row, parent, false);
        holder=new EmployeeHolder();
        holder.name=(TextView) convertView.findViewById(R.id.txtName);
        holder.age=(TextView) convertView.findViewById(R.id.txtAge);
        convertView.setTag(holder);
    }
    else
    {
        holder=(EmployeeHolder) convertView.getTag();
    }

    holder.name.setText(employeeArrayList.get(position).getName());
    holder.age.setText(String.valueOf(employeeArrayList.get(position).getAge()));

    return convertView;

}}

MainActivity.java

public class MainActivity extends Activity implements SearchView.OnQueryTextListener{
private SearchView mSearchView;
private ListView mListView;
private ArrayList<Employee> employeeArrayList;
private EmployeeAdapter employeeAdapter;

@Override
protected void onCreate(Bundle savedInstanceState)
{
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);
    mSearchView=(SearchView) findViewById(R.id.searchView1);
    mListView=(ListView) findViewById(R.id.listView1);

    employeeArrayList=new ArrayList<Employee>();
    employeeArrayList.add(new Employee("ABC", 24));
    employeeArrayList.add(new Employee("ACB", 24));
    employeeArrayList.add(new Employee("BVF", 28));
    employeeArrayList.add(new Employee("BRT", 28));
    employeeArrayList.add(new Employee("ANM", 23));

    employeeAdapter=new EmployeeAdapter(MainActivity.this, employeeArrayList);
    mListView.setAdapter(employeeAdapter);

    mListView.setTextFilterEnabled(true);
    setupSearchView();
    registerClickCallback();


}


private void registerClickCallback() {
    ListView list = (ListView) findViewById(R.id.listView1);
    list.setOnItemClickListener(new AdapterView.OnItemClickListener() {
        @Override
        public void onItemClick(AdapterView<?> parent, View view, int position, long id) {


            Employee pick = employeeArrayList.get(position);

            String message = "You Selected " + pick.getName();

            Toast.makeText(MainActivity.this, message, Toast.LENGTH_SHORT).show();

        }
    });
}

private void setupSearchView()
{
    mSearchView.setIconifiedByDefault(false);
    mSearchView.setOnQueryTextListener(this);
    mSearchView.setSubmitButtonEnabled(true);
    mSearchView.setQueryHint("Search Here");
}

@Override
public boolean onQueryTextChange(String newText)
{

    if (TextUtils.isEmpty(newText)) {
        mListView.clearTextFilter();
    } else {
        mListView.setFilterText(newText);
    }
    return false;
}

@Override
public boolean onQueryTextSubmit(String query)
{
    return false;
}}

提前谢谢！

Answer 1

简单，

在你的onItemClickListener（）中，尝试使用employeeadapter.getItem（）而不是employeearraylist.get（）。

尝试并对结果发表评论。：d

顺便说一下，您的适配器已经加载了回收物品的工作。将过滤负载放在它上面也不是一个好主意。

只需在您的活动内部进行过滤并使其返回一个arraylist并将列表适配器设置为此arraylist并再次调用setOnItemClickListener（）以更改现有的onItemClickListener（）。

Listview过滤器上的OnClickListener

1 个答案: